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3 years ago

What is AC?A) 4 cmB) 2.2 cmC) 9 cmD) 6 cmplease show your work

Mathematics

2 answers:

Papessa [141]3 years ago

8 0

Check the picture below.

Neko [114]3 years ago

6 0

The answer to your query is 9 centimeters. Hope this helps!

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skad [1K]

No because it's closer to 760,000

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3 years ago

Read 2 more answers

Answer then get brainliest :)

vfiekz [6]

Answer:

$\frac{2}{5} = \frac{6}{15} = \frac{12}{45}$

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2 years ago

3 times the sum of x and y squared plus 5 times the difference of 2x and y. (Using Distributive property)

BlackZzzverrR [31]

Answer: 3 times the sum of r and d squared minus 2 times the sum of r and d squared

we write the statement in terms of expression

⇒3×(r+d)²-2×(r+d)²=y

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3 0

3 years ago

4 men and 6 women are ranked according to their scores on an exam. Assume that no two scores are alike, and that all 10! 10 ! po

anygoal [31]

Answer:

a) $P(X=2)=\frac{2}{15}$

b) $P(X=3)=\frac{1}{30}$

c) P(X=6)=0

d) P(X=9)=0

Step-by-step explanation:

We know that are 4 men and 6 women are ranked according to their scores on an exam. X = 1 indicates that a man achieved the highest score on the exam.

a) We calculate P(X=2).

We calculate the number of possible combinations

$C^{10}_{2}=\frac{10!}{2! (10-2)!}=\frac{10\cdot 9\cdot 8!}{2\cdot 1 \cdot 8!}=45$

We calculate the number of favorable combinations

$C_2^4=\frac{4!}{2!(4-2)!}=6$

We get that is

$\boxed{P(X=2)=\frac{6}{45}=\frac{2}{15}}$

b) We calculate P(X=3).

We calculate the number of possible combinations

$C^{10}_{3}=\frac{10!}{3! (10-3)!}=\frac{10\cdot 9\cdot 8\cdot 7!}{3\cdot2\cdot 1 \cdot 7!}=120$

We calculate the number of favorable combinations

$C_3^4=\frac{4!}{3!(4-3)!}=4$

We get that is

$\boxed{P(X=3)=\frac{4}{120}=\frac{1}{30}}$

c) We calculate P(X=6). This case is not possible because 6 men cannot be selected because we have been given 4 men.

We conclude P(X=6)=0.

d) We calculate P(X=9). This case is not possible because 9 men cannot be selected because we have been given 4 men.

We conclude P(X=9)=0.

5 0

4 years ago

I need help with this review

Alla [95]

Answer:

can you just show the picture than just downloading it.

Step-by-step explanation:

5 0

3 years ago