Find the LCM of these numbers: 18, 27

The teacher passed out math books.The length is 10 inches and the width is 8 inches.What is the perimeter of each book?

miv72 [106K]

Answer: The perimeter of each book is: " 36 in. " .

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Step-by-step explanation:

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Note that the given units are all in "inches (in.)" .

Use the formula for the "perimeter of a rectangle" ;

{which happens to work for a "square" as well;

since a "square" is a rectangle.}.

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This is based on the assumption that the book is shaped like a

"rectangle" (or "square" —which is a rectangle).

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The formula for the Perimeter of a rectangle is:

P = 2 L + 2 w ;

in which:

P = the perimeter of the rectangle;

for which we shall solve; [in "inches (in.)" ] ;

L = the length of the rectangle = 10 in. (given) ;

w = the width of the rectangle = 8 in. (given) .

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Now, plug the given values for the "length (L)" and the "width (w)" ;

as follows:

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P = (2 * 10 in.) + (2 * 8 in.) ;

P = (20 in.) + (16 in.) ;

P = 36 in.

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Answer: The perimeter of each book is: " 36 in. " .

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Hope this helps!

Best wishes in your academic pursuits

— and within the "Brainly" community!

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3 0

3 years ago

Can someone help me with question please :) .

navik [9.2K]

Answer: C,D

Step-by-step explanation:

3 0

3 years ago

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Step 1: Place the graph paper in landscape orientation. Measure from the top left hand corner 6 inches right and 5 inches down.

cluponka [151]

T

<h3>How to determine the hypotenuse?</h3>

Step 1 and 2: Draw an isosceles right triangle

See attachment (figure 1) for this triangle

The legs of this triangle have a length of 1 inch

Step 3: The hypotenuse

This is calculated using the following Pythagoras theorem

$h^2 = 1^2 + 1^2$

This gives

$h = \sqrt 2$

Step 4: Draw another isosceles right triangle

Add 1 inch to one of the legs

See attachment (figure 2) for this triangle

The legs of this triangle have lengths of 1 inch and 2 inches, respectively

This hypotenuse is calculated using the following Pythagoras theorem

$h^2 = 2^2 + 1^2$

This gives

$h = \sqrt 5$

Step 5: Draw another isosceles right triangle

Add 1 inch to one of the legs

See attachment (figure 3) for this triangle

The legs of this triangle have lengths of 1 inch and 3 inches, respectively

This hypotenuse is calculated using the following Pythagoras theorem

$h^2 = 3^2 + 1^2$

This gives

$h = \sqrt {10$

Step 6: Draw another isosceles right triangle

Add 1 inch to one of the legs

See attachment (figure 4) for this triangle

The legs of this triangle have lengths of 1 inch and 4 inches, respectively

This hypotenuse is calculated using the following Pythagoras theorem

$h^2 = 4^2 + 1^2$

This gives

$h = \sqrt{[17$

See that the hypotenuse is the square root of 17

Hence, the right triangle whose legs are 1 inch and 4 inches has an hypotenuse of √17