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3 years ago

Use the situation below to complete the table and answer the questions,

Mathematics

1 answer:

Amiraneli [1.4K]3 years ago

5 0

Answer:

t = 13

Step-by-step explanation:

3 months ------ 4500

6 months ------ x

3/6 = 4500/x

cross multiplation:

3x =27000

x = 9000,or we should have just doubled the wages, since the time doubled

3 months ------ 4500

5 months ------ y

3/5 = 4500/y

3y = 22500

y = 7500

3 months ------- 4500

t months -------- 19500

3/t = 4500/19500 = 3/13

3t = 39

t = 13

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There are 2.54 centimeters in 1 inch. There are 100 centimeters in 1 meter.

amid [387]

Answer:

314.96in

Step-by-step explanation:

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3 years ago

Plssss help i give brainliest

notka56 [123]

Answer:

Length=2(x-1)

Width=5

Area=length*width = (2(x-1))(5) = (2x-2)(5) = 10x-10

His reasoning is illogical because whether or not an expression has a term that is being subtracted isn't relevant; technically there are an infinite amount of ways to represent a value. Plus you can just compute the expressions and see that they're equal:

6x-2x+4 = 4x+4

4(x-1) = 4x+4

The two expressions are equal because when you compute the expression 4(n+3)-(3+n) , you get 3n+9:

4(n+3)-(3+n) = 4n+12-3-n = 3n+9

The two expressions are equal because when you compute the expression 2(2n-1), you get 4n-2.

2(2n-1) = (2)(2n)+(2)(-1)=4n-2

5(g+14)=(5)(g)+(5)(14)=5g+70

The expressions aren't equal as 5(g+14) equates to 5g+70 and 5g+70≠5g+14.

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3 years ago

Ava and Kelly ran a road race, starting from the same place at the same time. Ava ran at an average speed of 6 miles per hour. K

zalisa [80]

<h2>Hello!</h2>

The answer is:

It will took 0.375 hours for Ava and Kelly to be 3/4 miles apart.

To calculate how long after they start they will be 3/4 miles apart, we need to write two equations.

So, writing the equations, we have:

Calculations for Ava:

We have the following information,

$v_{Ava}=6mph$

Then, writing the equation,

$x_{Ava}=x_{o}+v_{Ava}*t$

$x_{Ava}=x_{o}+v_{6mph}*t$

Calculations for Kelly:

We have the following information,

$v_{Kelly}=8mph$

We need to calculate when Kelly will be 3/4 miles apart of Ava, so, it's position will be the Ava's position plus 3/4 miles.

Then, writing the equation,

$x_{Ava}+0.75miles=x_{o}+v_{Kelly}*t$

$x_{Ava}+0.75miles=x_{o}+v_{8mph}*t$

Now, substituting Ava's speed into the second equation, we have:

$x_{o}+6mph*t+0.75miles=x_{o}+8mph*t$

$6mph*t+0.75miles=+8mph*t$

$8mph*t-6mph*t=0.75miles$

$2mph*t=0.75miles$

$t=\frac{0.75miles}{2mph}=0.375hours$

Hence, we have that it will took 0.375 hours for Ava and Kelly to be 3/4 miles apart.

Have a nice day!

7 0

3 years ago

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What’s the scale factor

dem82 [27]

Answer:

Step-by-step explanation:

The scale is depending on the size of each cat. Lets say the larger cat is A and the smaller one is B. The scale factor from B to A is 1.75 (or 3.5/2)

when solving for scale factor you divide the original drawing and scale drawing. Original is denominator, Scale is Numerator.

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3 years ago

Aaron estimated that 148% of 333 is 495

maksim [4K]

Answer:

492.84

Step-by-step explanation:

333 x 148÷100

= 492.84

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3 years ago

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