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Viefleur [7K]
3 years ago
5

Hello please help me with this I need an answer immediately thank you so much see image

Mathematics
1 answer:
hodyreva [135]3 years ago
8 0

For this case, we know that:

PA = PB

Then, by Pythagorean theorem (right triangle on the right) we have:

CP ^ 2 = CB ^ 2-PB ^ 2

So, again using the Pythagorean theorem (right triangle on the left) we have:

CA ^ 2 = CP ^ 2 + PB ^ 2

Substituting values:

CA ^ 2 = (CB ^ 2-PB ^ 2) + PB ^ 2

Rewriting:

CA ^ 2 = CB ^ 2

CA = CB

CA = 15

Answer:

The value of CA is given by:

CA = 15

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The manufacturer of an airport baggage scanning machine claims it can handle an average of 553 bags per hour. (a-1) At α = .05 i
timurjin [86]

Answer:

H1 : μ < 553. Reject H1 if tcalc > –1.753.

There is not enough evidence to reject the manufacturer’s claim.

Step-by-step explanation:

We are given that the manufacturer of an airport baggage scanning machine claims it can handle an average of 553 bags per hour.

A sample of 16 randomly chosen hours with a mean of 533 and a standard deviation of 47 is given.

Let \mu = <u><em>average bags that an airport baggage scanning machine can handle.</em></u>

SO, Null Hypothesis, H_0 : \mu \geq 553 bags     {means that the manufacturer’s claim is not overstated}

Alternate Hypothesis, H_0 : \mu < 553 bags     {means that the manufacturer’s claim is overstated}

The test statistics that would be used here <u>One-sample t-test statistics</u> as we don't know about population standard deviation;

                            T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean = 533 bags

            s = sample standard deviation = 47

            n = sample of hours = 16

So, <u><em>the test statistics</em></u>  =  \frac{533-553}{\frac{47}{\sqrt{16} } }  ~ t_1_5

                                     =  -1.702

The value of t test statistics is -1.702.

<u>Now, at 0.05 significance level the t table gives critical value of -1.753 at 15 degree of freedom for left-tailed test.</u>

Since our test statistic is more than the critical value of t as -1.702 > -1.753, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u><em>we fail to reject our null hypothesis</em></u>.

Therefore, we conclude that the manufacturer’s claim is not overstated and an airport baggage scanning machine can handle an average of 553 bags per hour.

5 0
3 years ago
The same digits are used for the expressions 34and 43.Explain how to compare the values of the expressions. whoever answers corr
Norma-Jean [14]

(3x10) + (4x1) = 34

(4x10) + (3x1) = 43

There are three tens in 34 and 4 tens in 43, and there are 4 ones in 34 and 3 ones in 43

Mark as Brainllest

8 0
3 years ago
A person whose eye level is 15 feet above the ground is looking at a building. The angle of elevation to the top of the building
uysha [10]

Answer:

61.97 feets

Step-by-step explanation:

Using trigonometry :

Horizontal distance between the person and building,

Let distance = d

Tan 15 = 15 / d

0.2679491 * d = 15

d = 15 / 0.2679491

d = 55.980781

To obtain the height, h :

tan 40 = (h-15)/d

d = 55.98

h-15 = 55.98 (tan 40°)

h - 15 = 55.98 * 0.8390996

h - 15 = 46.972797

h = 46.972797 + 15

h = 61.972797

h = 61.97 feets

4 0
3 years ago
PLEASE HELP!!! given ƒ(x) = x+1 and g(x) = x^2, what is (g o f) (x)?
kondor19780726 [428]

Step-by-step explanation:

(gof)(x)=(x+1)²

hope it helps

<h3>stay safe healthy and happy.</h3>
8 0
3 years ago
Calculate the median for the set of numbers:<br><br> 35, 33, 15, 32, 2, 28, 42
777dan777 [17]

Answer:

32

Step-by-step explanation:

To find the median, we need to put the numbers in order from smallest to largest

35, 33, 15, 32, 2, 28, 42

2, 15, 28, 32, 33, 35, 42

There are 7 numbers

7/2 = 3.5

So the 4th number is the median

2, 15, 28,    32,     33, 35, 42

32 is the 4th number

7 0
4 years ago
Read 2 more answers
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