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3 years ago

11

A recipe requires 2 1/3 cups of flour. the chef needs to increase the recipe by a factor of 4. how many cups of flour does the c

hef need?

1 answer:

Leona [35]3 years ago

3 0

2 × 4 = 8

1/3 × 4= 1 1/3

Total = 9 1/3 cups of flour

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Which point, (5/2, 3) or (3/2, 20), is on the graph of 2x - 2/3y =3?<br><br> show steps pls!

Anna11 [10]

You should try both points
put x=5/2 and y=3
5-2=3
the first one is on the graph
put x=3/2 and y=20
3-40/3≠3
the second one is not on the graph

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3 years ago

Can somebody please solve question 11 for me?

love history [14]

1+tan^2(A) = sec^2(A) [Pythagorean Identities]

tan^2(A)cot(A) = tan(A)[tan(A)cot(A)] = tan(A)[1] = tan(A)

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3 years ago

Multiply or divide as indicated b^7/ b^6

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<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ When values with exponents are divided, you should subtract the exponents.

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2 years ago

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Para reunir dinero para su gira de estudios , los alumnos de un curso deciden vender números de una rifa que se encuentran numer

QveST [7]

Respuesta:

0.53

Explicación:

Para calcular la posibilidad del evento A: "ganar la rifa comprando todos los números múltiplos de 3 o 5", debemos usar la siguiente fórmula.

P(A) = casos favorables / casos posibles

Evaluemos primero todos los casos que son múltiplos de 3, entre 1 y 100: 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, 66, 69, 72, 75, 78, 81, 84, 87, 90, 93, 96, 99. En total son 33.

Ahora, evaluemos todos los casos que son múltiplos de 3, entre 1 y 100: 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95, 100. En total son 20.

El número total de casos favorables es 33 + 20 = 53.

El número de casos posibles es el total de números de 1 a 100, es decir 100.

Luego P(A) = 53/100 = 0.53.

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2 years ago

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Vera_Pavlovna [14]

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3 years ago

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