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il63 [147K]
3 years ago
11

I am super bad with graphs

Mathematics
2 answers:
zavuch27 [327]3 years ago
4 0

this is my answer I hope its right I havent done graphs in a hot second

algol [13]3 years ago
4 0

Answer: not sure how i will be able to answer this. but ill see what i can do.

Step-by-step explanation:

  • (-5,3) is on the left side of the graph. Over 5 ((left way) = -5) and up
  • (2,-5) is one the right side of the graph. Over 2 (right way)  and down 5 from (0,0)
  • (3,3) is on the right side, over 3 and up 3
  • (5,-6) is on the right side, over 5 and down 6 from the (0,0)
  • (2,9) is on the right side over 2 and up 9.

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An air conditioning system can circulate 350 cubic feet of air

per minute. How many cubic yards of air can it circulate per

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About 13.0 cubic yards

8 0
3 years ago
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Sarah's sister has two summer jobs. The first job pays her $11 per hour. The second job pays her $14 per hour. In one month, she
telo118 [61]
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HELP ME PLEASEEEEEEE
Mamont248 [21]

Answer:

it's c

Step-by-step explanation:

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20 POINTS!!!!!! AND BRAINLY Solve this problem.
lapo4ka [179]
Hello! And thank you for your question!

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5 0
4 years ago
A survey in Men’s Health magazine reported that 39% of cardiologists said that they took vitamin E supplements. To see if this i
zzz [600]

Answer:

z=\frac{0.36 -0.39}{\sqrt{\frac{0.39(1-0.39)}{100}}}=-0.615  

The p value for this case would be:

p_v =2*P(z  

For this case since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true proportion is not different from 0.39

Step-by-step explanation:

Information given

n=100 represent the random sample taken

X=36 represent the number of people that take E supplement

\hat p=\frac{36}{100}=0.36 estimated proportion of people who take R supplement

p_o=0.39 is the value that we want to test

\alpha=0.05 represent the significance level

z would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true proportion is equatl to 0.39 or not, the system of hypothesis are.:  

Null hypothesis:p=0.39  

Alternative hypothesis:p \neq 0.39  

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the info we got:

z=\frac{0.36 -0.39}{\sqrt{\frac{0.39(1-0.39)}{100}}}=-0.615  

The p value for this case would be:

p_v =2*P(z  

For this case since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true proportion is not different from 0.39

8 0
3 years ago
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