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3 years ago

HELP IT"S ALGEBRA CAN SOMEONE DO THIS QUICK

Mathematics

2 answers:

Ahat [919]3 years ago

8 0

Answer:

(2,2)

Step-by-step explanation:

Katen [24]3 years ago

3 0

Answer:

I would have to say D.

Step-by-step explanation:

Sorry if I'm wrong

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Reduce fraction 27/36 lowest term

MAXImum [283]

If it 36/27 the answer is 1.33333 but if is 27/376 the answer will be 0.7 or 3/4

8 0

3 years ago

What is the coefficient of x2y3 in the expansion of (2x + y)5?

Zigmanuir [339]

Option C:

The coefficient of $x^{2} y^{3}$ is 40.

Solution:

Given expression:

$(2 x+y)^{5}$

Using binomial theorem:

$(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}$

Here $a=2 x, b=y$

Substitute in the binomial formula, we get

$(2x+y)^5=\sum_{i=0}^{5}\left(\begin{array}{l}5 \\i\end{array}\right)(2 x)^{(5-i)} y^{i}$

Now to expand the summation, substitute i = 0, 1, 2, 3, 4 and 5.

$$=\frac{5 !}{0 !(5-0) !}(2 x)^{5} y^{0}+\frac{5 !}{1 !(5-1) !}(2 x)^{4} y^{1}+\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}+\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}$

$$+\frac{5 !}{4 !(5-4) !}(2 x)^{1} y^{4}+\frac{5 !}{5 !(5-5) !}(2 x)^{0} y^{5}$

Let us solve the term one by one.

$$\frac{5 !}{0 !(5-0) !}(2 x)^{5} y^{0}=32 x^{5}$

$$\frac{5 !}{1 !(5-1) !}(2 x)^{4} y^{1} = 80 x^{4} y$

$$\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}= 80 x^{3} y^{2}$

$$\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}= 40 x^{2} y^{3}$

$$\frac{5 !}{4 !(5-4) !}(2 x)^{1} y^{4}= 10 x y^{4}$

$$\frac{5 !}{5 !(5-5) !}(2 x)^{0} y^{5}=y^{5}$

Substitute these into the above expansion.

$(2x+y)^5=32 x^{5}+80 x^{4} y+80 x^{3} y^{2}+40 x^{2} y^{3}+10 x y^{4}+y^{5}$

The coefficient of $x^{2} y^{3}$ is 40.

Option C is the correct answer.

5 0

3 years ago

I need the incomplete fraction answer for: y= z= b= Thx

sergejj [24]

Answer:

Y = 15sqrt(3)/4

Z = 15sqrt(3)/2

b = 45/4

Step-by-step explanation:

Sin(60) =Z/15

sqrt(3)/2 = Z/15

Z = 15sqrt(3)/2

Sin(30) = Y/Z

½ = Y/Z

Y = ½(15sqrt(3))/2 = 15sqrt(3)/4

Cos(30) = b/Z

sqrt(3)/2 = b/Z

b = 15sqrt(3)/2 × sqrt(3)/2

b = 45/4

sqrt is square root/radical

8 0

3 years ago

Read 2 more answers

Which of the following absolute value equations has no solutions?Group of answer choices

Amiraneli [1.4K]

The absolute value measures the distance a number is away from the origin (zero) on the number line. A number can be to the left or right of zero on the number line, but the distance away from zero is always positive. Graphically:

In other words:

• If d is positive and

$\begin{gathered} |x|=d \\ \text{ then} \\ x=d\text{ or }x=-d \end{gathered}$

• If d is negative and

$\begin{gathered} |x|=-d \\ \text{then} \\ \text{ No solution, because distance (d) can not be negative.} \end{gathered}$

Therefore, the equation that has no solutions is:

$\boldsymbol{|x|=-3}$

3 0

1 year ago

The mass of a tiger at a zoo is 235 kilograms. Randy's cat has a mass of 5,000 grams. How many times greater is the mass of tige

ANTONII [103]

Solutions

We know that the mass of a tiger at a zoo is 235 kilograms. Randy's cat has a mass of 5,000 grams. To solve the problem we have to convert 235 kilograms into grams.

235 kilograms = 235000 grams

Randy's cat has a mass of 5,000 grams

Randy's cat = 5,000 grams

Tiger = 235000 grams

Our next step is to subtract 5000 from 235000 grams

235000 grams - 5000 grams = 230000

Answer = 230000 grams

6 0

3 years ago

Read 2 more answers