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malfutka [58]
3 years ago
10

Cot^2x-csc^2x= please include the steps thank you !!will give branliest ​

Mathematics
1 answer:
tamaranim1 [39]3 years ago
6 0

Answer:

Step-by-step explanation:                                                                                      One of the fundamental identities is #1+cot^2(x) = csc^2(x)#.

Starting with your given:

#cot^2(x)-csc^2(x)#

Replace #csc^2(x)# with #1+cot^2(x)#:

#cot^2(x)-(1+cot^2(x))#

#=cot^2(x)-1-cot^2(x))#

#=-1#

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SVETLANKA909090 [29]

Answer:

f[g(1)]=6.

Explanation:

Given f(n) and g(n) defined below:

\begin{gathered} f\mleft(n\mright)=n^2-3 \\ g\mleft(n\mright)=4n-1 \end{gathered}

First, we evaluate g(1):

\begin{gathered} g\mleft(1\mright)=4(1)-1 \\ =4-1 \\ g(1)=3 \end{gathered}

Therefore:

\begin{gathered} f\mleft(g(1)\mright)=f\mleft(3\mright) \\ f\mleft(3\mright)=3^2-3 \\ =9-3 \\ =6 \end{gathered}

Therefore, f[g(1)]=6.

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1 year ago
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