Question

F(n) = n² – 3 g(n) = 4n - 1 Find f[g(1)]

Answer 1

Answer:

f[g(1)]=6.

Explanation:

Given f(n) and g(n) defined below:

$\begin{gathered} f\mleft(n\mright)=n^2-3 \\ g\mleft(n\mright)=4n-1 \end{gathered}$

First, we evaluate g(1):

$\begin{gathered} g\mleft(1\mright)=4(1)-1 \\ =4-1 \\ g(1)=3 \end{gathered}$

Therefore:

$\begin{gathered} f\mleft(g(1)\mright)=f\mleft(3\mright) \\ f\mleft(3\mright)=3^2-3 \\ =9-3 \\ =6 \end{gathered}$

Therefore, f[g(1)]=6.