Answer:
Chi-square analysis cannot be used to check for significant difference in the number of knee injuries among four sports.
Explanation:
The chi-square analysis is a statistical procedure that is used to test association between measured variables or goodness of fits of a set of measured variables to expected outcomes.
<em>In the case of testing for significant difference, chi-square analysis cannot be used as testing for significant difference in two or more means requires using t-test, analysis of variance, or any other relevant statistical procedure.</em>
To compare number of knee injuries reported among four sports for significant difference, the most suitable statistical procedure would be analysis of variance.
<em />
The correct answer is stabilizing selection reduces the amount of variation in a trait. disruptive selection increases the amount of variation in a trait.
Stabilizing selection is a type of natural selection in which genetic diversity decreases because natural selection favours an average phenotype and selects against extreme variations.
<span>
Disruptive selection is a type of natural selection in which extreme values for a trait are favoured over intermediate values, thus it increases genetic variance.</span>
Answer:
The article is not reflecting current knowledge.
Explanation:
Rick Potts had explained some thing which has already been established and published several years back by various scientist, researchers, biologist, ecologists and geologist.
Re publishing something again will not bring laurel to Pott, instead his article would not be considered a suitable article for reference.
Also , if Pott would have published any thing that talks of a way ahead of those previous publication, even then his article could be referred.
Answer:
Most probably it would die. Or would be harder for it to live.
Explanation:
On daily basis, as most of the cells die and new cells are formed by cell division. If an organism lost the ability to perform cell division it would die.
Answer:
No, bones grow first to develop a frame for the muscle to grow on.
PXL