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horsena [70]
3 years ago
7

Explain me PLEASEEEE!!!

Mathematics
1 answer:
kirza4 [7]3 years ago
8 0

Answer:

\frac{(a^{2})^{3}.a^{-3}}{a^{10}}=\frac{a^{6}.a^{-3}}{a^{10}}=\frac{a^{3}}{a^{10}}=a^{-7}=\frac{1}{a^{7}}

Step-by-step explanation:

Let us revise the properties of exponents

  • a^{m}.a^{n}=a^{m+n}
  • \frac{a^{m}}{a^{n}}=a^{m-n}
  • (a^{m})^{n}=a^{m.n}
  • a^{-m}=\frac{1}{a^{m} }

Let us use these properties to solve the question

→ By using the 3rd property above

∵ (a^{2})^{3}=a^{2.3}=a^{6}

∴ \frac{(a^{2})^{3}.a^{-3}}{a^{10}}=\frac{a^{6}.a^{-3}}{a^{10} }

→ By using the 1st property above

∵ a^{6}.a^{-3}=a^{6+-3}=a^{6-3}=a^{3}

∴  \frac{(a^{2})^{3}.a^{-3}}{a^{10}}=\frac{a^{6}.a^{-3}}{a^{10}}=\frac{a^{3}}{a^{10}}

→ By using the 2nd property above

∵ \frac{a^{3}}{a^{10}}=a^{3-10}=a^{-7}

∴  \frac{(a^{2})^{3}.a^{-3}}{a^{10}}=\frac{a^{6}.a^{-3}}{a^{10}}=\frac{a^{3}}{a^{10}}=a^{-7}

→ By using the 4th property above

∵ a^{-7}=\frac{1}{a^{7}}

∴  \frac{(a^{2})^{3}.a^{-3}}{a^{10}}=\frac{a^{6}.a^{-3}}{a^{10}}=\frac{a^{3}}{a^{10}}=a^{-7}=\frac{1}{a^{7}}

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MN is parallel to PO. Find each unknown angle measure.<br> 24<br> ON<br> 22°<br> M<br> S
tatiyna

Answer:

Step-by-step explanation:

MN // PO

∠OMN =∠POM     { alternate interior angles}

∠OMN  = 34

∠PMO + ∠OMN + ∠1 = 180  {STRAIGHT LINE}

22 + 34 +∠1 = 180

56 +∠1 = 180

∠1 = 180 - 56

∠1 = 124

∠OPM  =∠1   { Corresponding angles, PO//MN AND PM IS TRANSVERSL}

∠OPM = 124

3 0
3 years ago
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Answer:

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Step-by-step explanation:

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skelet666 [1.2K]

Hi There!

----------------------------------------

Problem #1:

At the dealership where she works, Sade fulfilled 3/10 of her quarterly sales goal in January and another 1/10 of her sales goal in February. What fraction of her quarterly sales goal had Sade reached by the end of February?

3/10 + 1/10 = 4/10

4/10 of her goal.

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Problem #2:

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1/10 + 9/10 = 10/10 = 1

Shane drove 1 mile.

----------------------------------------

Problem #3:

For a class experiment, Vina's class weighed a log before and after subjecting it to termites. Before subjecting it to termites, the log weighed 7/10 of a pound. After the termites, the log weighed 3/10 of a pound. How much weight did the termites take from the log?

7/10 - 3/10 = 4/10

The termites took 4/10 pound away from the log.

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Hope This Helps :)

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3 years ago
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