All categories

3 years ago

I need help on find the mean, median, mode, or range

Mathematics

1 answer:

Bogdan [553]3 years ago

8 0

Answer:

Median

Step-by-step explanation:

You need to arrange the numbers in order by size.

Then if there is an odd number of terms the median in the middle term. If there is is an even amount of terms then what you do is add 2 then divide by 2

You might be interested in

Which lists these numbers in order from least to greatest? –14.6, 159, 1.07, –1.295, 24.6

Monica [59]

c is the answer because negative numbers have to go first

4 0

2 years ago

Help meeeeee with this! No links!

Gelneren [198K]

Answer:

There is a mistake in Step 2. Maya distributed 3(x-10) as 3x+30, which is false. The correct step is: 6x+12 = 3x-30

Then solve for x

The answer is B. Maya made a mistake between Step 1 and Step 2 because she did not correctly distribute 3 to (x-10).

3 0

2 years ago

In Triangle PQR, PQ = 9, QR = 10, and RP = 12. What is the smallest angle of this triangle?

KatRina [158]

Answer:

Step-by-step explanation:

8 0

2 years ago

For the following pair of functions, find (f+g)(x) and (f-g)(x).

ch4aika [34]

Given:

The functions are

$f(x)=4x^2+7x-5$

$g(x)=-9x^2+4x-13$

To find:

The functions $(f+g)(x)$ and $(f-g)(x)$ .

Solution:

We know that,

$(f+g)(x)=f(x)+g(x)$

$(f+g)(x)=4x^2+7x-5-9x^2+4x-13$

$(f+g)(x)=(4x^2-9x^2)+(7x+4x)+(-5-13)$

$(f+g)(x)=-5x^2+11x-18$

And,

$(f-g)(x)=f(x)-g(x)$

$(f-g)(x)=(4x^2+7x-5)-(-9x^2+4x-13)$

$(f+g)(x)=4x^2+7x-5+9x^2-4x+13$

$(f+g)(x)=(4x^2+9x^2)+(7x-4x)+(-5+13)$

$(f-g)(x)=13x^2+3x+8$

Therefore, the required functions are $(f+g)(x)=-5x^2+11x-18$

and $(f-g)(x)=13x^2+3x+8$ .

7 0

3 years ago

Need help plsssss :;):5:$//&-&!.&/).:$83

Katyanochek1 [597]

The answer is b.

Because you multiply (5•12)

3 0

3 years ago