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vova2212 [387]
3 years ago
11

In a right triangle ABC, CD is the angle bisector of the right angle C. Two lines DF and DE are parallel to the legs of the tria

ngle. Prove that DFCE is a square.
find the following
m∠CED = 180° − m∠ _____ = ___ by reason ________
m∠CFD = 180° − m∠ _____ = ___ by reason ________
Mathematics
1 answer:
Tcecarenko [31]3 years ago
7 0
<span>m∠CED = 180° − m∠DEB= 90 degrees, by reason corresponding angles of parallel lines are congruent
</span>m∠CFD = 180° − m∠AFD = 90 degrees by reason corresponding angles of parallel lines are congruent
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(7,-1) and (6, 6)
vova2212 [387]

Answer:

y=-7x+48 slope would be -7

Step-by-step explanation:

Used a Regression Calculator

3 0
2 years ago
Mrs. Davis went to a produce market to buy bananas and strawberries. She spent $8.00. If the bananas were $0.50 per pound, and t
9966 [12]

9514 1404 393

Answer:

  4 pounds

Step-by-step explanation:

Let b represent the pounds of bananas Mrs. Davis bought. The weight of strawberries would be (7-b) and their cost would be 4×0.50 = 2.00 per pound. Her total purchase was ...

  0.50b + 2.00(7 -b) = 8.00

  -1.50b +14 = 8 . . . . simplify

  6 = 1.50b . . . . . . add 1.50b -8

  4 = b . . . . . . . . divide by 1.50

Mrs. Davis bought 4 pounds of bananas.

7 0
2 years ago
Least to greatest -6.8,|-23/4|,0,-14.4,|-1.9|,5.4
IrinaVladis [17]

Answer:

From Least to Greatest: -14.4, -6.8, -23/4, -1.9, 0, 5.4

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Which points are on the perpendicular bisector of the given segment? Check all that apply. Please explain how you got your answe
ser-zykov [4K]
First, you have to find the equation of the perpendicular bisector of this given line. 
to do that, you need the slope of the perpendicular line and one point.
Step 1: find the slope of the given line segment. We have the two end points (10, 15) and (-20, 5), so the slope is m=(15-5)/(10-(-20))=1/3
the slope of the perpendicular line is the negative reciprocal of the slope of the given line, m=-3/1=-3 
step 2: find the middle point: x=(-20+10)/2=-5, y=(15+5)/2=10      (-5, 10)
so the equation of the perpendicular line in point-slope form is (y-10)=-3(x+5)

now plug in all the given coordinates to the equation to see which pair fits:
(-8, 19): 19-10=9, -3(-8+5)=9, so yes, (-8, 19) is on the perpendicular line. 

try the other pairs, you will find that (1,-8) and (-5, 10) fit the equation too. (-5,10) happens to be the midpoint. 

4 0
2 years ago
Read 2 more answers
Solve for x<br><br> 3(ax + 9) = -4 (-2 - 10x)
ivolga24 [154]

Answer:

19

-----   =   x

40-3a

Step-by-step explanation:

3(ax + 9) = -4 (-2 - 10x)

Distribute

3ax +27 = 8+40x

Subtract 3ax from each side

3ax-3ax +27 = 8+40x-3ax

27 = = 8+40x-3ax

Subtract 8 from each side

27-8 = 8-8+40x-3ax

19 = 40x-3ax

Factor an x on the right side

19 = x(40-3a)

Divide each side by 40-3a

19/(40-3a) = x(40-3a)/(40-3a)

19

-----   =   x

40-3a

8 0
2 years ago
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