Answer:
(2,-7)
Step-by-step explanation:
I think its that
Answer:
the answer is 17
Step-by-step explanation:
6×3-1
= 17
Answer:
There is a 0.82% probability that a line width is greater than 0.62 micrometer.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.
In this problem
The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so
.
What is the probability that a line width is greater than 0.62 micrometer?
That is 
So



Z = 2.4 has a pvalue of 0.99180.
This means that P(X \leq 0.62) = 0.99180.
We also have that


There is a 0.82% probability that a line width is greater than 0.62 micrometer.
Measure 1 would be 59 degrees (180-121)
Measure 2 would be 121 degrees (vertical angle theorem)
Answer:

Step-by-step explanation:
We are given that The monthly charge for a waste collection service is 1830 dollars for 100 kg of waste
So, 
We are also given that The monthly charge for a waste collection service is 2460 dollars for 135 kg of waste.
So, 
We are supposed to find a linear model for the cost, C, of waste collection as a function of the number of kilograms, w.
So, we will use two point slope form :
Formula : 
Substitute the values





y denotes the cost
x denotes the weight
So, Replace y with C and x with w

So, a linear model for the cost, C, of waste collection as a function of the number of kilograms, w is 