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lakkis [162]
3 years ago
7

I will give u brainliest

Mathematics
2 answers:
dem82 [27]3 years ago
7 0

Answer:12.8

Step-by-step explanation:

Arisa [49]3 years ago
3 0

Answer:

12.8

Step-by-step explanation:

Trust me

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What is the sin inverse of (sine 9pi/7)?
Sveta_85 [38]
For the answer to the question above, I've used my calculator to inverse your given equation because my brain can't do that.
The answer to your question is
In radians, arcsin(sin(9π) / 7) = 0.
 i hope my answer helped you.

7 0
3 years ago
Write 5 5/9 as a improper fraction
4vir4ik [10]
5 5/9
5 * 5/9
25/9
The correct answer is 25/9, as shown above.
3 0
2 years ago
What is the simplified base of the function f(x) = One-fourth (Root Index 3 StartRoot 108 EndRoot) Superscript x?
Rainbow [258]

Answer:

The base is: 3 \sqrt[3]{4}

Step-by-step explanation:

Given

f(x) = \frac{1}{4}(\sqrt[3]{108})^x

Required

The base

Expand 108

f(x) = \frac{1}{4}(\sqrt[3]{3^3 * 4})^x

Rewrite the exponent as:

f(x) = \frac{1}{4}(3^3 * 4)^\frac{1}{3}^x

Expand

f(x) = \frac{1}{4}(3^3^\frac{1}{3} * 4^\frac{1}{3})^x

f(x) = \frac{1}{4}(3 * 4^\frac{1}{3})^x

Rewrite as:

f(x) = \frac{1}{4}(3 \sqrt[3]{4})^x

An exponential function has the following form:

f(x)=ab^x

Where

b \to base

By comparison:

b =3 \sqrt[3]{4}

So, the base is: 3 \sqrt[3]{4}

4 0
3 years ago
A 555-mile, 5-hour plane trip was flown at two speeds. For the first part of the trip, the average speed was 105 mph. Then the t
Pepsi [2]

Answer:

Hence Distance traveled at speed 115 mph is <u>345 miles</u> and Distance traveled at speed 105 mph is <u>210 miles</u>.

Step-by-step explanation:

Given:

Total Distance = 555 mile

Total time = 5 hour

Let time taken to travel at 115 mph be t

So Time taken to travel at 105 mph will be equal to difference between Total time and  time taken to travel at 115 mph.

Time taken to travel at 105 mph = 5-t

Distance traveled in speed 105 mph will be equal to speed multiplied by time taken to travel at 105 mph.

Framing in equation form we get;

Distance traveled in 115 mph = 115t

Also;

Distance traveled in speed 105 mph will be equal to speed multiplied by time taken to travel at 105 mph.

Framing in equation form we get;

Distance traveled in 105 mph = 105(t-5) = 105t - 525

Now Total Distance traveled is equal sum of Distance traveled in 115 mph and Distance traveled in speed 105 mph

115t-(105t-525)=555\\\\115t-105t+525=555\\\\10t+525=555\\\\10t=555-525\\\\10t=30\\\\t=\frac{30}{10}=3

Time taken to travel at 115 mph = 3 hrs.

Time taken to travel at 105 mph = 5-t=5-3=2\ hrs

Now Distance traveled in 115 mph = 115t = 115 \times 3 = 345\ miles

Distance traveled in 105 mph = 105(5-t) = 105(5-3)= 105\times 2 = 210\ miles

Hence Distance traveled at speed 115 mph is <u>345 miles</u> and Distance traveled at speed 105 mph is <u>210 miles</u>.

6 0
3 years ago
Ginni founded Waggstooth Manor Doggie Day Care and after a year in business, formed a partnership with her husband, Warren. Thei
Inessa [10]

Answer:

Ginni and Waren

Step-by-step explanation:

Here both Ginni and ware are partners in the Company after a year when ginni founded it.

Both Ginni and Waren are risk, because both the partners have unlimited personal liability so it does not matter who owns the larger share of the company. The risk will be equal on both the partners whereas Phebe here is at the least risk .

5 0
3 years ago
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