Answer:
Step-by-step explanation:
This is already factored for us, which is really nice, so now all we need to do is apply the Zero Product Property to the sets of parenthesis and solve for x, which will give us the 2 times that the object is on the ground.
x + 1 = 0 so
x = -1
x - 9 = 0 so
x = 9
We all know that time cannot ever be negative, so the time that the object is on the ground is 9 seconds after it's launched (which was from an initial height of 45 meters).
Answer:
x+10
Step-by-step explanation:
Answer :V=πr2h=π·72·11≈1693.31844
Step-by-step explanation:
Answer:
4-4=0
16-6-10=0
17-3-4-10=0
1-2+1=0
Step-by-step explanation:
Answer:
![y=\frac{c}{\sqrt[]{x^2+1} }](https://tex.z-dn.net/?f=y%3D%5Cfrac%7Bc%7D%7B%5Csqrt%5B%5D%7Bx%5E2%2B1%7D%20%7D)
Step-by-step explanation:
(1 + x²)dy +xydx= 0
Integrate both side
![lny=-\frac{1}{2} ln(x^2+1)+c\\y=\frac{c}{\sqrt[]{x^2+1} }](https://tex.z-dn.net/?f=lny%3D-%5Cfrac%7B1%7D%7B2%7D%20ln%28x%5E2%2B1%29%2Bc%5C%5Cy%3D%5Cfrac%7Bc%7D%7B%5Csqrt%5B%5D%7Bx%5E2%2B1%7D%20%7D)
