Answer: H is 5 and K is 2
Step-by-step explanation:
Answer:
The speed of the jet in still air is 415 mph and the speed of the wind is 19 mph
Step-by-step explanation:
we know that
The speed is equal to divide the distance by the time
Let
x -----> the speed of the wind in miles per hour
y ----> the speed of the jet in still air in miles per hour
we know that
<em>With a tailwind</em>

----> equation A
<em>With a headwind</em>

----> equation B
solve the system of equations A and B by elimination
Adds equation A and equation B

<em>Find the value of x</em>



therefore
The speed of the jet in still air is 415 mph and the speed of the wind is 19 mph
Answer: X=7/2
Step-by-step explanation:
Answer:
The speed of Kali is 30 mph.
Step-by-step explanation:
Let, the speed of Kali be "x", then speed of Ndiba will be:
Speed of Ndiba = x + 15 mph
If, the time for travel for Ndiba is 2 hrs, when he catches Kali, and he left 1 hour later than Kali, then then time traveled by Kali at that instant will be 2+1 = 3hrs.
At the point of meeting both will have covered same distance.
Distance Covered by Kali = Distance Covered by Ndiba
(Speed of Kali)(Time traveled by Kali) = (Speed of Ndiba)(Time traveled by Ndiba)
(x)(3) = (x +15)(2)
3x = 2x +30
<u>x = 30 mph</u>
The correct answer is, actually 30 mph, by the solution shown above.
-4 since -4*-15=60
also gcd (60,15)=15
so 60/15=4/1