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2 years ago

6

A caterpillar moves across the grass at a rate of 423 feet every 7 minutes. How fast does the caterpillar move in feet per minut

e?

1 answer:

bija089 [108]2 years ago

7 0

If it moves 423 feet in 7 minutes, you divide 423 by 7 to see how much it moves per minute, which is Around 60.4 feet per minute

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Which expression has a value of 7/12 ? 7/8 + 4 , 1/3 + 1/4 , 6/8 + 1/4 , 2 1/12 + 5 1/12

vazorg [7]

Answer:

$\frac{1}{3} + \frac{1}{4}$

Step-by-step explanation:

We want to find an expression that has a value of

$\frac{7}{12}$

First option:

$\frac{7}{8} + 4 = \frac{7}{8} + \frac{32}{8} = \frac{39}{8} \ne \frac{7}{12}$

Second option:

$\frac{1}{3} + \frac{1}{4} = \frac{4}{12} + \frac{3}{12} = \frac{7}{12}$

Correct option

Third option

$\frac{6}{8} + \frac{1}{4} = \frac{3}{4} + \frac{1}{4} = 1$

Fourth option:

$2 \frac{1}{12} + 5 \frac{1}{12} = \frac{43}{6}$

5 0

3 years ago

-3/v=-6 simply as much as possible

Aleksandr [31]

Hey!

In order to simplify this equation, we'll first have to multiply both sides of the equation by v. This will give us v on its own.

<em>Original Equation :</em>
$\frac{-3}{v} = -6$

<em>New Equation {Added Multiply Both Sides by V} :</em>
$\frac{-3}{v} v=-6v$

<em>Solution {New Equation Solved} :</em>
$-3 = -6v$

Now we'll switch sides to get v on the left side of the equation which is generally where we always want the variables to be located in these types of equations.

<em>Old Equation :</em>
$-3 = -6v$

<em>New Equation {Switched} :</em>
$-6v=-3$

Now we'll divide both sides by v to get v on its own.

<em>Old Equation :</em>
$-6v = -3$

<em>New Equation {Added Divide Both Sides by V} :</em>
$\frac{-6v}{v} = \frac{-3}{v}$

<em>Solution {New Equation Solved} :</em>
$v = \frac{1}{2}$

<em>So, this means that in the equation $\frac{-3}{v} =-6$ ,</em> $v = \frac{1}{2}$ .

Hope this helps!

- Lindsey Frazier ♥

3 0

3 years ago

If the distance covered by an object in time t is given by s(t)=t^2+5t , where s(t) is in meters and t is in seconds, what is th

alisha [4.7K]

Answer:

E. 44 meters

Step-by-step explanation:

The function that models the distance covered by the object is

$s(t)=t^2+5t$

where s(t) is in meters and t is in seconds.

The distance covered by the object after 1 second is

$s(1)=1^2+5(1)=6m$

The distance covered by the object after 1 second is

$s(1)=5^2+5(5)=50m$

The distance covered between 1 second and 5 seconds is

50-6=44m

6 0

3 years ago

hey, i have this question for algebra nation and i have no clue how to work this problem out... can you please help me?

irina1246 [14]

In algebra the notation is basically just a number, for example, 10, and we take it to the 10th power, you just take the decimal at the end of the 10 and move it 10 spaces to the right, if the number is negative you will move the decimal to the left 10 spaces, the 10th power is a variable and is different with every question

8 0

3 years ago

David leaves the house to go to school. He walks 160m west and 290m north. To the nearest tenth, how far away is he from his sta

zavuch27 [327]

Answer:

50m

Step-by-step explanation:

7 0

3 years ago