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3 years ago

Can someone help me please? What is 6 times 6 plus 9 divided by 10 in the second power?

Mathematics

1 answer:

Dovator [93]3 years ago

5 0

First of all, it would be easier to write down this problem, wouldn't it? ;)

6 x 6 + 9 ÷ 10^2

According to PEMDAS, we will start off with the exponent part of the equation, since there are no parenthesis.

10^2 = 100

Now, we will multiply 6 x 6, which equals 36.

Then, you will divide 9 by 100, which makes 0.09. Now we can add 0.09 to 36 and see what we get as a final answer.

0.09 + 36 = 36.09

FINAL ANSWER --

36.09

↑ ↑ ↑ Hope this helps! :D

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Answer:

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Step-by-step explanation:

So I believe the problem is this:

$\frac{2(4x+3)}{x-3}(x+7)}=\frac{a}{x-3}+\frac{b}{x+7}$

where we are asked to find values for $a$ and $b$ such that the equation holds for any $x$ in the equation's domain.

So I'm actually going to get rid of any domain restrictions by multiplying both sides by (x-3)(x+7).

In other words this will clear the fractions.

$\frac{2(4x+3)}{x-3}(x+7)}\cdot(x-3)(x+7)=\frac{a}{x-3}\cdot(x-3)(x+7)+\frac{b}{x+7}(x-3)(x+7)$

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As you can see there was some cancellation.

I'm going to plug in -7 for x because x+7 becomes 0 then.

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Divide both sides by -10:

$\frac{-50}{-10}=b$

$5=b$

Now we have:

$2(4x+3)=a(x+7)+b(x-3)$ with $b=5$

I notice that x-3 is 0 when x=3. So I'm going to replace x with 3.

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$2(12+3)=a(10)+b(0)$

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Divide both sides by 10:

$\frac{30}{10}=a$

$3=a$

So $a=3$ and $b=5$ .

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Answer:

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Step-by-step explanation:

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