Answer: For the sum of 130
First: $90
Second: $40
Step-by-step explanation:
We write equations for each part of this situation.
<u>The Total Charge</u>
Together they charged 1550. This means 1550 is made up of the first mechanics rate for 15 hours and the second's rate for 5 hours. Lets call the first's rate a, so he charges 15a. The second's let's call b. He charges 5b. We add them together 15a+5b=1550.
<u>The Sum of the Rates</u>
Since the first's rate is a and the second is b, we can write a+b=130 since their sum is 130.
We solve for a and b by substituting one equation into another. Solve for the variable. Then substitute the value into the equation to find the other variable.
For a+b=130, rearrange to b=130-a and substitute into 15a+5b=1550.
15a + 5 (130-a)=1550
15a+650-5a=1550
10a+650-650=1550-650
10a=900
a=$90 was charged by the first mechanic.
We substitute to find the second mechanic's rate.
90+b=130
90-90+b=130-90
b= $40 was charged by the second mechanic
y=6x-3
put a point on (0,-3) this is your y intercept
go up 6 and over 1 this should land you at (1,0) do this again and your at (2,6)
go back to the y intercept now go down 6 and over 1, this should land you (-1,-6)
continue to do this until you graph is filled
Answer:
The answer to the first one is 6
Step-by-step explanation:
If the time frame given is 9 months, then we can find that 9 months is 3/4 of a year. 3/4 x 2% = 0.015. 0.015 x 400 = 6. He would have made 6 dollars in 9 months.
Answer the the second one:
4.5% x 5 (years) = 0.225. 0.225 x 10,000 = 2,250. Since this is a car loan and not a bank interest for example, we add it to the total cost. I'm pretty sure its the third one.
Answer:
by <u>AAS</u>
Step-by-step explanation:
According to the following two triangles,
and
are congruent by <u>Angle-Angle-Side</u> (AAS), because there are two angles shown and share a side, which is in the middle between triangles.
Answer:
<h2>
<em>3</em><em>9</em><em> </em><em>units</em></h2>
<em>Solution,</em>
<em>Total </em><em>area=</em><em>Area </em><em>of </em><em>ABCD+</em><em> </em><em>Area </em><em>of </em><em>triangle </em><em>ADE</em>
<em>
</em>
<em>hope </em><em>this </em><em>helps.</em><em>.</em><em>.</em>
<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em>