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pav-90 [236]
3 years ago
5

Tawnee is designing a playground in the shape of a rectangle. If Tawnee increases the length and width of the playground by a sc

ale factor of 2
what will be the resulting effect on the perimeter of the new playground?
The perimeter of the new playground will be half the perimeter of the original playground
The perimeter of the new playground will be 1/4 the perimeter of the original playground
The perimeter of the new playground will be twice the perimeter of the original playground
O The perimeter of the new playground will be four times the perimeter of the original playground
Mathematics
2 answers:
Sphinxa [80]3 years ago
5 0

Answer:

I think it is the 3rd one The perimeter of the new playground will be twice the perimeter of the original playground

Step-by-step explanation:

give brainliest plz

svetlana [45]3 years ago
4 0

Answer:

We conclude that If Tawnee increases the length and width of the playground by a scale factor of 2, the perimeter of the new playground will be twice the perimeter of the original playground.

Step-by-step explanation:

We know that the perimeter of a rectangle = 2(l+w)

i.e.

P = 2(l+w)

Here

  • 'l' is the length
  • 'w' is the width

Given that the length and width of the playground by a scale factor of 2

A scale factor of 2 means we need to multiply both length and width by 2.

i.e

P = 2× 2(l+w)

P' = 2 (2(l+w))

    = 2P      ∵ P = 2(l+w)

Therefore, we conclude that If Tawnee increases the length and width of the playground by a scale factor of 2, the perimeter of the new playground will be twice the perimeter of the original playground.

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Answer:

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Step-by-step explanation:

7 0
3 years ago
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2 years ago
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Brums [2.3K]

The area of the shaded region is  \rm (150\sqrt{3} \ - 75\pi ) \ feet^2 option first is correct.

It is given that a circle is inscribed in a regular hexagon with sides of 10 feet.

It is required to find the shaded area (missing data is attached shown in the picture).

<h3>What is a circle?</h3>

It is defined as the combination of points that and every point has an equal distance from a fixed point ( called the center of a circle).

We have a hexagon with a side length of 10 feet.

We know the area of the hexagon is given by:

\rm A = \frac{3\sqrt{3} }{2} a^2  where a is the side length.

\rm A = \frac{3\sqrt{3} }{2} 10^2 ⇒ 150\sqrt{3} \rm feet^2

We have the shortest length = x feet and from the figure:

2x = 10

x = 5 feet

The radius of the circle r = longer leg

\rm r = x\sqrt{3} \Rightarrow 5\sqrt{3} feet

The area of the circle a = \pi r^2  ⇒ \pi (5\sqrt{3} )^2 \Rightarrow 75\pi \ \rm feet^2  

The area of the shaded region = A - a

\rm =(150\sqrt{3} \ - 75\pi ) \ feet^2

Thus, the area of the shaded region is  \rm (150\sqrt{3} \ - 75\pi ) \ feet^2

Learn more about circle here:

brainly.com/question/11833983

7 0
1 year ago
A school baseball team earned $3416.90 from selling 5716 tickets to their game. If grandstand tickets sold for 65 cents each and
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Let g and b represent the numbers of grandstand and bleacher tickets sold.
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.. 65g +40b = 341690 . . value of tickets sold

Using the first equation
.. g = 5716 -b
Sustituting into the second equation
.. 65(5716 -b) +40b = 341690
.. -25b + 371540 = 341690 . . . . . collect terms
.. -25b = -29850 . . . . . . . . . . . . . . subtract 371540
.. b = 1194 . . . . . . . . . . . . . . . . . . . . divide by -25

1194 bleacher tickets were sold.
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3 years ago
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