Tawnee is designing a playground in the shape of a rectangle. If Tawnee increases the length and width of the playground by a sc
ale factor of 2 what will be the resulting effect on the perimeter of the new playground?
The perimeter of the new playground will be half the perimeter of the original playground
The perimeter of the new playground will be 1/4 the perimeter of the original playground
The perimeter of the new playground will be twice the perimeter of the original playground
O The perimeter of the new playground will be four times the perimeter of the original playground
We conclude that If Tawnee increases the length and width of the playground by a scale factor of 2, the perimeter of the new playground will be twice the perimeter of the original playground.
Step-by-step explanation:
We know that the perimeter of a rectangle = 2(l+w)
i.e.
P = 2(l+w)
Here
'l' is the length
'w' is the width
Given that the length and width of the playground by a scale factor of 2
A scale factor of 2 means we need to multiply both length and width by 2.
i.e
P = 2× 2(l+w)
P' = 2 (2(l+w))
= 2P ∵ P = 2(l+w)
Therefore, we conclude that If Tawnee increases the length and width of the playground by a scale factor of 2, the perimeter of the new playground will be twice the perimeter of the original playground.
You have two sets of parallel sides. A square has two sets of parallel sides, and it has the extra condition that all of the angles are right angles. So a square is definitely going to be a rhombus. Now, all rhombuses have four sides.
