Sue's total pay of year will have three parts
1) Fixed Salary for 12 months
one month salary = £1410
so 12 month salary = £1410 x 12 = £16920
2) 26% of total profit
Total cost to the company- £473,500
Total income for the company - £549,000
Profit = Total income for the company - Total cost to the company
= £549,000 - £473,500 = £75500
Sues income from profit = 26% of £75500 = (26 × 75500)/100 = £19630
3) Bonus if Sue sells at least 16 cars
Given number of months when sue solds atleast 16 cars = 4
So bonus income = 4 × 390 = £1560
Adding the three above parts
Sue's total pay for the year = £16920 + £19630 + £1560 = £38110
9514 1404 393
Answer:
C log3(√((x -4)/x)
Step-by-step explanation:
The applicable rules of logarithms are ...
log(a/b) = log(a) -log(b)
log(a^n) = n·log(a)
The base is irrelevant, as long as all logs are to the same base.
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Given situation: There were 548 films released in 2011. Rated PG were approximately 8.75% of the released movie.
Question: Find how many PG movies were released in 2011. PG means Parental guidance.
Solution,
=> 8.75% = 8.75 / 100 = 0.0875
=> Now, let’s multiply this decimal number to the total number of films released.
=> 548 * 0.0875
=> 47.95. Round off to 50.
Thus, there were approximately 50 films released that were Rated PG.
<span>f(t) = 94*1.25992105^t
Since the value doubles every three years we want an X such that
X^3 = 2
Or in simpler terms, our growth rate is the cube root of 2. So lets get that. To calculate the nth root of a number you can take the logarithm of the number, divide by n, then get the anti-log. So
10^(log(2)/3) = 10^(0.301029996/3) = 10^0.100343332 = 1.25992105
Now the function becomes trivial. I'll use t as the number of years since the baseline capacity was calculated (94 thousand megawatts at t = 0). So
f(t) = 94*1.25992105^t</span>
