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Svetllana [295]
3 years ago
9

Etermine whether the conjecture is true or false. Give a counterexample for any false conjecture.

Mathematics
1 answer:
Schach [20]3 years ago
7 0
I dont know if m2 is the variable or its suppose to be m(2)
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Doss [256]
9*2 =18 add 27 =45 this is the answer hope this helped
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3 years ago
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What is the answer for 3÷4-1
umka2103 [35]

Answer:

-1/4 OR -0.25

Step-by-step explanation:

Using PEMDAS:

3/4 = 3/4... or 0.75.

Subtracting 1: 3/4 - 4/4 (or 1) = -1/4. 0.75 - 1 = -0.25.

5 0
3 years ago
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If the population of
Dahasolnce [82]
It would take 32 minutes.

1,000 * 32 = 32,000
3 0
1 year ago
You have won the lottery and will receive 20 annual payments of $10,000 starting today. If you can invest these payments at 8.5%
xxTIMURxx [149]

Answer:

$102,677.20

Step-by-step explanation:

The present value of an annuity due is determined by the following expression:

PV = P+P*(\frac{1-(1+r)^{-n+1}}{r})

Where 'P' is the amount of each payment received, 'r' is the interest rate on the investment and 'n' is the number of yearly payments.

With 20 annual payments of $10,000 at a rate of 8.5%, the present value is:

PV = 10,000+10,000*(\frac{1-(1+0.085)^{-20+1}}{0.085})\\PV = 10,000+ 10,000*(9.26772)\\PV=\$102,677.20

The present value of your winnings is $102,677.20.

8 0
3 years ago
Some of the students three scores is 231. If the first is 20 points more than the second, and the sum of the first two is 6 more
Aleks [24]

Answer:

The first score is 109

Step-by-step explanation:

I am assuming that in the first sentence of the question, you meant:

Sum of the students three scores is 231...

First, let the scores of the first second and third student be a, b and c respectively. We are told that:

a + b + c = 231 . . . . . . . .(1)         (sum of students three scores is 231)

a = b + 20 . . . . . . . . . . . (2)        (the first is 20 points more than the second)

a + b = 6c . . . . . . . . . . . .(3)        (sum of the first two is 6 more times the third)

required, find a.

substituting the value of (a + b) in equation (3) into equation (1), we will have the following:

since a + b = 6c . . . (3)

a + b + c = 231 . . . . . (1), becomes,

(a + b) + c = 231

(6c)  + c = 231

7c = 231 (divide both sides by 7)

c = 231 ÷ 7 = 33

∴ c = 33

Next, from equation (2), we know that a = b + 20; this can also be written as:

a - 20 = b

∴ b = a - 20 . . . . . . . (4)

Finally, putting the value of b in equation (4) and the value of c calculated above into equation 1, ( a + b + c = 231), we have the following:

a + (a - 20) + 33 = 231

(a + a) - 20 + 33 = 231

2a + 13 = 231

2a = 231 - 13 = 218

a = 218 ÷ 2 = 109

∴ a = 109

we can also calculate for 'b' by substituting for the value of 'a' in equation 4

b = a - 20 = 109 - 20 = 89.

and to test if the values of a, b and c are correct:

a + b + c = 231

109 + 89 + 33 = 231

4 0
3 years ago
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