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Sergio039 [100]
3 years ago
8

Find the 53rd term of the arithmetic sequence 27,11, -5

Mathematics
1 answer:
vivado [14]3 years ago
3 0

Answer:

The 53rd term of this arithmetic sequence is -805.

Step-by-step explanation:

The general rule of an arithmetic sequence is the following:

a_{n+1} = a_{n} + d

In which d is the common diference between each term, that is, d = a_{3} - a_{2} = a_{2} - a_{1}.

To find the nth term of the sequence, this equation can be written as:

a_{n} = a_{1} + (n-1)d

27,11, -5

So a_{1} = 27, a_{2} - a_{1} = 11 - 27 = -16[/tex[tex]a_{n} = a_{1} + (n-1)d

a_{53} = a_{1} + (52)d = 27 + 52*(-16) = -805

The 53rd term of this arithmetic sequence is -805.

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Answer:

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Step-by-step explanation:

So we have 1.245245245245.... which we call x.

If we times this by 1000 (because 3 digits repeat) we get

1000x = 1245.245245245....

Subtract x from both sides:

999x = 1245.245245245... - 1.245245... = 1244

This means that x = 1244/999

This fraction cannot be simplified so this is the answer.

If you want to include the 1 in the repeating (1.2451245...) do the same but the sequence is 4 digits so times by 10000 instead.

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Answer:

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Step-by-step explanation:

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