A process that produces computer chips has a mean of .04 defective chips and a standard deviation of .003 chips. The allowable v
1 answer:
Answer:
The capability index for the process is 0.889
Step-by-step explanation:
Here, we want to compute the capability index for the process
To get this, we need some important parameters which we already have stated in the question
USL ( upper standard limit) = 0.048
LSL (lower standard limit) = 0.032
mean = 0.04
standard deviation = 0.003
We apply the formula as seen in the attachment below
Kindly understand that we are to calculate the Z upper and Z lower
The smallest value between the two will be our Z minimum
This is what we shall apply in the capability index formula which mathematically is;
Z minimum/3
From calculation:
Z lower = Z upper = 2.67
So therefore;
capability index = 2.67/3 = 0.889
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Answer:
11 ft
Step-by-step explanation:
Given the two lengths of a triangle as
AB = 6ft
AC = 6ft
This is an isosceles triangle because only 2 sides are equal.
In an isosceles triangle, the sum of 2 (sides) lengths must be greater than the other length.
Therefore, let's assume the following:
i) AC + AB > BC
6 + 6 > BC
12 > BC (BC is less than 12)
BC < 12
ii) BC + AC > AB
BC + 6 > 6
BC > 6 - 6
BC > 0
Therefore the range of values for BC =
0 < BC < 12
Since BC must be bigger than one of the lengths and it must also be less than the sum of the 2 sides. The length of BC could be 11 because it is less than (6+6) 12 and greater than 6.
