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ASHA 777 [7]
3 years ago
8

I need it step by step​

Mathematics
1 answer:
elena-s [515]3 years ago
4 0

Answer:

Step-by-step explanation:

we want y by itself...sooo

y - 19 = - \frac{6}{10}(x - (-5))

y - 19 = - \frac{6}{10}(x+5)

y - 19 =  - \frac{6}{10}x - \frac{6}{2}

y = - \frac{6}{10}x - 3 +19

y = - \frac{6}{10}x + 16

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Anis that cosine and sine?

Step-by-step explanation:

8 0
3 years ago
What is the exact volume of the cylinder?
AURORKA [14]

Answer:

1178.25cm^3

Step-by-step explanation:

Volume of a cylinder is given as V = Pi x r^2 xh

PI= 3.142

R = 5cm

H=15cm

So volume = 3.142 x 5cm x 5cm x 15cm

= 1178.25cm^3

4 0
3 years ago
A large pool of adults earning their first driver’s license includes 50% low-risk drivers, 30% moderate-risk drivers, and 20% hi
Mamont248 [21]

Answer:

The probability that these four will contain at least two more high-risk drivers than low-risk drivers is 0.0488.

Step-by-step explanation:

Denote the different kinds of drivers as follows:

L = low-risk drivers

M = moderate-risk drivers

H = high-risk drivers

The information provided is:

P (L) = 0.50

P (M) = 0.30

P (H) = 0.20

Now, it given that the insurance company writes four new policies for adults earning their first driver’s license.

The combination of 4 new drivers that satisfy the condition that there are at least two more high-risk drivers than low-risk drivers is:

S = {HHHH, HHHL, HHHM, HHMM}

Compute the probability of the combination {HHHH} as follows:

P (HHHH) = [P (H)]⁴

                = [0.20]⁴

                = 0.0016

Compute the probability of the combination {HHHL} as follows:

P (HHHL) = {4\choose 1} × [P (H)]³ × P (L)

               = 4 × (0.20)³ × 0.50

               = 0.016

Compute the probability of the combination {HHHM} as follows:

P (HHHL) = {4\choose 1} × [P (H)]³ × P (M)

               = 4 × (0.20)³ × 0.30

               = 0.0096

Compute the probability of the combination {HHMM} as follows:

P (HHMM) = {4\choose 2} × [P (H)]² × [P (M)]²

                 = 6 × (0.20)² × (0.30)²

                 = 0.0216

Then the probability that these four will contain at least two more high-risk drivers than low-risk drivers is:

P (at least two more H than L) = P (HHHH) + P (HHHL) + P (HHHM)

                                                            + P (HHMM)

                                                  = 0.0016 + 0.016 + 0.0096 + 0.0216

                                                  = 0.0488

Thus, the probability that these four will contain at least two more high-risk drivers than low-risk drivers is 0.0488.

6 0
3 years ago
José sets up computers. He has been working
lakkis [162]
Correct answer should be= 1.5 hours.
3 0
3 years ago
Please help ASAP!!!!!
ra1l [238]
These tables have infinitely many values, but the simplest ones would be:
a) x|y
    3|5
    6|10
    9|15

b) x|y
    2|1
    4|2
    6|3

Your graph for c would look like the attached picture

7 0
3 years ago
Read 2 more answers
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