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morpeh [17]
2 years ago
10

To solve for x in the equation x - 4 = 19, which inverse operation would you

Mathematics
2 answers:
lara31 [8.8K]2 years ago
5 0
Add 4 to both sides......
Mazyrski [523]2 years ago
3 0
Add 4 to both sides :)
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3 years ago
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tuesday: -28.5

Wednesday: -5

Thursday: -11.8

Friday: -4.5

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3 years ago
Adam is rewriting the expression 8^5/8^2
zhuklara [117]

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8^3

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3 years ago
At a local swimming pool, the diving board is elevated h = 9.5 m above the pool's surface and overhangs the pool edge by L = 2 m
beks73 [17]
<h2>Answer:</h2>

s_{y}=u_{y}t+\frac{1}{2}a_{y}t^{2}\\9.5=4.9t^{2}

and,

v_{x}=1.39a_{x}+2.5

<h2>Step-by-step explanation:</h2>

In the question,

Taking the elevation of pool along the y-axis, and length of the board along the x-axis.

On drawing the illustration in the co-ordinate system we get,

lₓ = 2 m

uₓ = 2.5 m/s

and,

h_{y}=9.5\,m

So,

From the equations of the laws of motion we can state that,

s_{y}=u_{y}t+\frac{1}{2}a_{y}t^{2}

So,

On putting the values we can say that,

s_{y}=u_{y}t+\frac{1}{2}a_{y}t^{2}\\9.5=(0)t+\frac{1}{2}(9.8)t^{2}\\t^{2}=\frac{9.5}{4.9}\\t^{2}=1.93\\t=1.39\,s

Now,

The <u>equation of the motion in the horizontal</u> can be given by,

v_{x}=u_{x}+a_{x}t\\v_{x}=2.5+a_{x}(1.39)\\So,\\v_{x}=1.39a_{x}+2.5

<em><u>Therefore, the equations of the motions in the horizontal and verticals are,</u></em>

s_{y}=u_{y}t+\frac{1}{2}a_{y}t^{2}\\9.5=4.9t^{2}

and,

v_{x}=1.39a_{x}+2.5

6 0
3 years ago
Please help. I’ll mark you as brainliest if correct!!!!! <br> ON B!
k0ka [10]

Answer:

5 dollars

Step-by-step explanation:

multiply 100 and 1.25 and get 125 then 130 minus 125 is 5 hope this helps god bless

7 0
3 years ago
Read 2 more answers
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