I’m so confused ahhhhh

Is this problem correct?

Strike441 [17]

Answer:

Yes that is correct. B is correct.

Step-by-step explanation:

When you plug 0 in for x, the result is 3.

When you plug 1 in for x, the result becomes 1.

The equation matches up correctly.

f(x) = -2x + 3

#teamtrees #WAP (Water And Plant)

8 0

3 years ago

Read 2 more answers

Two samples were taken of fish caught on Small Lake and are shown in the table below. It is estimated that the Sm

kolezko [41]

Answer:

its 80 on edg

Step-by-step explanation:

6 0

3 years ago

The fact that sin(150°) = .5 and sin(-150°) = -.5 implies that the sine function is which type of function?

Naddika [18.5K]

Answer: A) Odd

In general, sin(-x) = -sin(x) for all values of x, so it's an odd function. I don't mean it's a strange function. I mean "odd" in the sense that it's not even (eg: the number 7 is an odd number).

4 0

3 years ago

Tom has 12 ears of field corn to make

Leviafan [203]

Tom arranged 3 groups of 4

5 0

3 years ago

Rocky Mountain National Park is a popular park for outdoor recreation activities in Colorado. According to U.S. National Park Se

erastovalidia [21]

Answer:

a) 0.6628 = 66.28% probability that at least 85 visitors had a recorded entry through the Beaver Meadows park entrance

b) 0.5141 = 51.41% probability that at least 80 but less than 90 visitors had a recorded entry through the Beaver Meadows park entrance

c) 0.5596 = 55.96% probability that fewer than 12 visitors had a recorded entry through the Grand Lake park entrance.

d) 0.9978 = 99.78% probability that more than 55 visitors have no recorded point of entry

Step-by-step explanation:

Using the normal approximation to the binomial.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

In this problem, we have that:

175 visitors, so $n = 175$

a)

46.7% through the Beaver Meadows, so $p = 0.467$

$\mu = E(X) = np = 175*0.467 = 81.725$

$\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{175*0.467*0.533} = 6.6$

This probability, using continuity correction, is $P(X \geq 85 - 0.5) = P(X \geq 84.5)$ , which is 1 subtracted by the pvalue of Z when X = 84.5. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{84.5 - 81.725}{6.6}$

$Z = 0.42$

$Z = 0.42$ has a pvalue of 0.6628.

66.28% probability that at least 85 visitors had a recorded entry through the Beaver Meadows park entrance.

b)

This is $P(80 - 0.5 \leq X < 90 - 0.5) = P(79.5 \leq X \leq 89.5)$ , which is the pvalue of Z when X = 89.5 subtracted by the pvalue of Z when X = 79.5. So