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Advocard [28]
3 years ago
9

Confused on how to write the equation due to the graph having a point at (1,2).

Mathematics
1 answer:
kari74 [83]3 years ago
5 0

Answer:

The line passes through (1,2) and (4,4)

The equation,

\frac{y - y1}{x - x1}  =  \frac{y2 - y1}{x2 - x1}

\frac{y - 2}{x - 1}  =  \frac{4 - 2}{4 - 1}  =  \frac{2}{3}

3(y - 2) = 2(x - 1)

=  > 3y - 6 = 2x - 2

=  > 2x - 3y - 2 + 6 = 0

=  > 2x - 3y + 4 = 0

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S=k/v(s)+1/v(s) in terms of v(s)
otez555 [7]

Answer:

            k + 1

v(s) = -------------

                S

Step-by-step explanation:

Solve the equation S=k/v(s)+1/v(s) for v(s).

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3 0
3 years ago
Read 2 more answers
The temperature outside dropped 13 degrees in 7 hours.The final temperature was -2 degrees.What was the starting temperature
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11 degrees

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7 0
2 years ago
What is the radius of a circle whose equation is x2 y2 8x – 6y 21 = 0?
andrew11 [14]

we know that

the standard form of the equation of the circle is

(x-h)^{2} +(y-k)^{2}=r^{2}

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(h,k) is the center of the circle

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In this problem we have

x^{2} +y^{2} +8x-6y+21=0

<u>Convert to standard form</u>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(x^{2}+8x) +(y^{2}-6y)=-21

Complete the square twice. Remember to balance the equation by adding the same constants to each side.

(x^{2}+8x+16) +(y^{2}-6y+9)=-21+16+9

(x^{2}+8x+16) +(y^{2}-6y+9)=4

Rewrite as perfect squares

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the radius of the circle is 2\ units

therefore

<u>the answer is</u>

the radius of the circle is 2\ units


8 0
3 years ago
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