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Advocard [28]
3 years ago
9

Confused on how to write the equation due to the graph having a point at (1,2).

Mathematics
1 answer:
kari74 [83]3 years ago
5 0

Answer:

The line passes through (1,2) and (4,4)

The equation,

\frac{y - y1}{x - x1}  =  \frac{y2 - y1}{x2 - x1}

\frac{y - 2}{x - 1}  =  \frac{4 - 2}{4 - 1}  =  \frac{2}{3}

3(y - 2) = 2(x - 1)

=  > 3y - 6 = 2x - 2

=  > 2x - 3y - 2 + 6 = 0

=  > 2x - 3y + 4 = 0

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HELP ASAP (Geometry)
Andrei [34K]

1) Parallel line: y=-2x-3

2) Rectangle

3) Perpendicular line: y = 0.5x + 2.5

4) x-coordinate: 2.7

5) Distance: d=\sqrt{(4-3)^2+(7-1)^2}

6) 3/8

7) Perimeter: 12.4 units

8) Area: 8 square units

9) Two slopes of triangle ABC are opposite reciprocals

10) Perpendicular line: y-5=-4(x-(-1))

Step-by-step explanation:

1)

The equation of a line is in the form

y=mx+q

where m is the slope and q is the y-intercept.

Two lines are parallel to each other if they have same slope m.

The line given in this problem is

y=-2x+7

So its slope is m=-2. Therefore, the only line parallel to this one is the line which have the same slope, which is:

y=-2x-3

Since it also has m=-2

2)

We can verify that this is a rectangle by checking that the two diagonals are congruent. We have:

- First diagonal: d_1 = \sqrt{(-3-(-1))^2+(4-(-2))^2}=\sqrt{(-2)^2+(6)^2}=6.32

- Second diagonal: d_2 = \sqrt{(1-(-5))^2+(0-2)^2}=\sqrt{6^2+(-2)^2}=6.32

The diagonals are congruent, so this is a rectangle.

3)

Given points A (0,1) and B (-2,5), the slope of the line is:

m=\frac{5-1}{-2-0}=-2

The slope of a line perpendicular to AB is equal to the inverse reciprocal of the slope of AB, so:

m'=\frac{1}{2}

And using the slope-intercept for,

y-y_0 = m(x-x_0)

Using the point (x_0,y_0)=(7,1) we find:

y-1=\frac{1}{2}(x-7)

And re-arranging,

y-1 = \frac{1}{2}x-\frac{7}{2}\\y=\frac{1}{2}x-\frac{5}{2}\\y=0.5x-2.5

4)

The endpoints of the segment are X(1,2) and Y(6,7).

We have to divide the sgment into 1/3 and 2/3 parts from X to Y, so for the x-coordinate we get:

x' = x_0 + \frac{1}{3}(x_1 - x_0) = 1+\frac{1}{3}(6-1)=2.7

5)

The distance between two points A(x_A,y_A) and B(x_B,y_B) is given by

d=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}

In this problem, the two points are

E(3,1)

F(4,7)

So the distance is given by

d=\sqrt{(4-3)^2+(7-1)^2}

6)

We have:

A(3,4)

B(11,3)

Point C divides the segment into two parts with 3:5 ratio.

The distance between the x-coordinates of A and B is 8 units: this means that the x-coordinate of C falls 3 units to the right of the x-coordinate of A and 5 units to the left of the x-coordinate of B, so overall, the x-coordinate of C falls at

\frac{3}{3+5}=\frac{3}{8}

of the  distance between A and B.

7)

To find the perimeter, we have to calculate the length of each side:

d_{EF}=\sqrt{(x_E-x_F)^2+(y_E-y_F)^2}=\sqrt{(-1-2)^2+(6-4)^2}=3.6

d_{FG}=\sqrt{(x_G-x_F)^2+(y_G-y_F)^2}=\sqrt{(-1-2)^2+(3-4)^2}=3.2

d_{GH}=\sqrt{(x_G-x_H)^2+(y_G-y_H)^2}=\sqrt{(-1-(-3))^2+(3-3)^2}=2

d_{EH}=\sqrt{(x_E-x_H)^2+(y_E-y_H)^2}=\sqrt{(-1-(-3))^2+(6-3)^2}=3.6

So the perimeter is

p = 3.6 + 3.2 + 2 + 3.6 = 12.4

8)

The area of a triangle is

A=\frac{1}{2}(base)(height)

For this triangle,

Base = XW

Height = YZ

We calculate the length of the base and of the height:

Base =XW=\sqrt{(x_X-x_W)^2+(y_X-y_W)^2}=\sqrt{(6-2)^2+(3-(-1))^2}=5.7

Height =YZ=\sqrt{(x_Y-x_Z)^2+(y_Y-y_Z)^2}=\sqrt{(7-5)^2+(0-2)^2}=2.8

So the area is

A=\frac{1}{2}(XW)(YZ)=\frac{1}{2}(5.7)(2.8)=8

9)

A triangle is a right triangle when there is one right angle. This means that two sides of the triangle are perpendicular to each other: however, two lines are perpendicular when their slopes are opposite reciprocals. Therefore, this means that the true statement is

"Two slopes of triangle ABC are opposite reciprocals"

10)

The initial line is

y=\frac{1}{4}x-6

A line perpendicular to this one must have a slope which is the opposite reciprocal, so

m'=-4

Using the slope-intercept form,

y-y_0 = m'(x-x_0)

And using the point

(x_0,y_0)=(-1,5)

we find:

y-5=-4(x-(-1))

Learn more about parallel and perpendicular lines:

brainly.com/question/3414323

brainly.com/question/3569195

#LearnwithBrainly

8 0
3 years ago
If x) = 4x^2 + 1 and g(x) = x^2 - 5, find (f + g)(x).​
Vedmedyk [2.9K]

Answer:

C. 5x² - 4

General Formulas and Concepts:

<u>Algebra I</u>

  • Composite Functions
  • Combining Like Terms

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = 4x² + 1

g(x) = x² - 5

(f + g)(x) is f(x) + g(x)

<u>Step 2: Find (f + g)(x)</u>

  1. Substitute:                    (f + g)(x) = 4x² + 1 + x² - 5
  2. Combine like terms:    (f + g)(x) = 5x² - 4
8 0
3 years ago
The gas mileage of Car A is 21 miles per gallon. The gas mileage of Car B is 30 miles per gallon. Which of the following graphs
Anna [14]

Answer:

c for plato users;)

Step-by-step explanation:

8 0
3 years ago
Mark has a piece of wood 4 1/4 feet long. Tony has a piece of wood 1 2/4 feet long. How much wood do the boys have altogether. p
Alona [7]
They have 5 3/4 ft

4+1=5
1/4+2/4=3/4


but hey, its not the length of your wood that matters, its how you use it XD
8 0
3 years ago
For what values of c does the binomial 5-3c take on a value which is greater than 80?
Ganezh [65]
Answer: c > -25

From the question you can get the equation:
5 - 3c > 80; subtract 5 from both side
-3c > 75; divide -3 from both side
c > -25
So numbers including: -24, -23, -22, -21…
are all numbers that could work
7 0
3 years ago
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