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2 years ago

Evaluate 10b + 3c, if b=3 and c = 11.

Mathematics

1 answer:

kozerog [31]2 years ago

4 0

Answer:

Step-by-step explanation:

10 × 3 = 30

3× 11 = 33

30 + 33 = 63

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Please help me .! 10 points .!

BaLLatris [955]

The answer is 19 I subtracted the 2 biggest numbers

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3 years ago

Y is inversely proportional to the square of (x + 2). When x = 3, y = 2. Find y when x = 8.

VikaD [51]

Answer:

y = k/(x+2) squared

substitute y and x to find the value of k.

k =50

nxt used the value of k with same formula:.

y= 50/ (8+2) squared

y =1/2

6 0

2 years ago

Determine whether each expression can be used to find the length of side AB. Match Yes or No for each

tankabanditka [31]

Answer:

$(a)\ AB = \frac{7}{\sin (B)}$ $\to Yes$

$(b)\ AB = \frac{24}{\cos (B)}$ $\to Yes$

$(c)\ AB = \frac{24}{\cos (A)}$ $\to No$

$(d)\ AB = \frac{7}{\cos (A)}$ $\to Yes$

Step-by-step explanation:

Given

$BC =24$

$AC = 7$

Required

Select Yes or No for the given options

$(a)\ AB = \frac{7}{\sin (B)}$ $\to Yes$

Considering the sine of angle B, we have:

$\sin(B) = \frac{Opposite}{Hypotenuse}$

$\sin(B) = \frac{7}{AB}$

Make AB, the subject

$AB = \frac{7}{\sin(B)}$

$(b)\ AB = \frac{24}{\cos (B)}$ $\to Yes$

Considering the cosine of angle B, we have:

$\cos(B) = \frac{Adjacent}{Hypotenuse}$

$\cos(B) = \frac{24}{AB}$

Make AB the subject

$AB = \frac{24}{\cos(B)}$

$(c)\ AB = \frac{24}{\cos (A)}$ $\to No$

Considering the cosine of angle B, we have:

$\cos(A) = \frac{Adjacent}{Hypotenuse}$

$\cos(A) = \frac{7}{AB}$

Make AB the subject

$AB = \frac{7}{\cos(A)}$

$(d)\ AB = \frac{7}{\cos (A)}$ $\to Yes$

This has been shown in (c) above

3 0

3 years ago

Simplify. (3m^2n4)^3 A)27m^5n^7 B)9m^6n12 C)27m^6n^12 D)9m^5n^7

butalik [34]

(3m²n⁴)³ = 27m^6n^12. choice C

6 0

4 years ago

Can u help me with this

Nimfa-mama [501]

4b - 7 + 2b + 11 and b + 3 + b + 1 are congruent.

You add the common factors in each problem: 2b + 4 = 2b + 4

4 0

3 years ago