Factor the equation. Remember the value should add to the b value and multiply to the c value.
x^2-x-12= 0
(x-4)(x+3)=0
Use the zero product property to find roots
x-4=0
x=4
x+3=0
x=-3
Final answer: x=-3, x=4
Answer:
![(2,8]](https://tex.z-dn.net/?f=%282%2C8%5D)
Step-by-step explanation:
Given
The attached piece wise function
Required
The domain
To do this, we simply consider the inequalities that bound the values of x.
The inequalities are:
and 
Combine the first two inequalities:
and 
For the inequality to be true, we must have:

In interval notation, the inequality is:
![(2,8]](https://tex.z-dn.net/?f=%282%2C8%5D)
Answer:
infinitely many
Step-by-step explanation:
Rewrite these equations as
y = (1/2)x + 1
2y = x + 2
and then solve the second for y: y = (1/2)x + 1. Note that these end results are identical. The two lines coincide; that is, one lies right on top of the other. Thus, there are infinitely many solutions.
5 : - 1/6 = 0.167 out of 10 = 1.67 out of 100 = 16.7
even number 0.33 out of 10:- 3.3 out of 100:- 33
a prime number 0.5 out of 10: 5 and out of 100:- 50
multipl of 3:- 0/33 out of 10:- 3.3 and out of 100: 33
Answer:
The equation has no solutions
Step-by-step explanation:
If we re arrange the equation a little more we will obtain the following
|x|=-11
Which is a contradiction since, the |x| is always a positive number
Attached is the representation of this function y= |x|
It means, that it doesnt matter what value 'x' has, the answer is the same number but, positive