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FrozenT [24]
3 years ago
6

Factor by grouping 3n^3 - 12n^2 + 2n - 8 (show the work pls..)

Mathematics
1 answer:
densk [106]3 years ago
8 0

Answer:

The answer will be <u>( n - 4 ) ( 3n² + 2 ).</u>

Step-by-step explanation:

1) Factor out common terms in the first two terms, then in the last two terms.

{3n}^{2} (n - 4) + 2(n - 4)

2) Factor out the common term n - 4.

(n - 4)( {3n}^{2}  + 2)

<u>Therefor</u><u>,</u><u> </u><u>the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>( n - 4 ) ( 3n² + 2 ).</u>

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