Question

Factor by grouping 3n^3 - 12n^2 + 2n - 8 (show the work pls..)

Answer 1

Answer:

The answer will be ( n - 4 ) ( 3n² + 2 ).

Step-by-step explanation:

1) Factor out common terms in the first two terms, then in the last two terms.

${3n}^{2} (n - 4) + 2(n - 4)$

2) Factor out the common term n - 4.

$(n - 4)( {3n}^{2} + 2)$

Therefor, the answer is ( n - 4 ) ( 3n² + 2 ).