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3 years ago

I need help with my math work!!!!!!

Mathematics

2 answers:

Anna007 [38]3 years ago

8 0

The first one is the correct answer

zalisa [80]3 years ago

6 0

Answer:

The answer is the first one

Step-by-step explanation:

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What is 8 wholes and 3/4 subtracted by 2 wholes and 1/4

Pepsi [2]

6 wholes and 2/4))hhh

5 0

3 years ago

A boutique handmade umbrella factory currently sells 37500 umbrellas per year at a cost of 7 dollars each. In the previous year

slega [8]

Answer:

$302,500

Step-by-step explanation:

If cost (C) = $7, then Sales (S) = 37,500 units

If cost (C) = $15, then Sales (S) = 17,500 units

The slope of the linear relationship between units sold and cost is:

$m=\frac{37,500-17,500}{7-15}\\m= -2,500$

The linear equation that describes this relationship is:

$s-s_0 =m(c-c_0)\\s-17500 =-2500(c-15)\\s(c)=-2500c + 55,000$

The revenue function is given by:

$R(c) = c*s(c)\\R(c)=-2500c^2 + 55,000c$

The cost at which the derivative of the revenue equals zero is the cost that yields the maximum revenue.

$\frac{d(R(c))}{dc}=0 =-5000c + 55,000\\c=\$11$

The optimal cost is $11, therefore, the maximum revenue is:

$R(11)=-2500*11^2 + 55,000*11\\R(11)=\$ 302,500$

4 0

3 years ago

Consider a tank used in certain hydrodynamic experiments. After one experiment the tank contains 200 L of a dyesolution with a c

nordsb [41]

Answer:

Time,t that it will elapse before the concerntration of the dye in the tank reaches1% of its original value is 460.52 seconds

Step-by-step explanation:

Let Q(t) = amount of dye for all time,t.

Let Q'= rate in - rate out.

But Q/200 = concerntration of dye

Therefore rate out= Q/200 ×2.

Q'/Q = - 1/100

Dividing by Q gives

Ln/Q/ + c = -1/100t + c1

Integrating both sides with respect to t

Ln/Q/ = -1/100t + c2.

c1 and c1 are just another constants

Q= c3e^-t/100

Exponentiating both sides will cause the absolute values to get absorbed into the constants giving rise to a new constant c3

200= c3-0/100

c3= 200

2= 200e^-t/100

Ln1/100= - t/100

Ln0.01 = - t/ 100

Cross multiply

t= Ln0.01 × 100

t = 4.6052 ×100

t = 460.52seconds

7 0

3 years ago

Help me with the question in the pic

Nonamiya [84]

Answer:

208

Step-by-step explanation:

With shapes like these, it's easier to break it into two squares. Area is width times height, and you know the taller square has a width of 6 and height of 16, so the area of that would be 96.

For the other square, subtract the 6 from the 14 to get the width, 8. For the height, subtract the 2 from the 16, and you get 14. 14x8 is 112.

Now add the two areas together, and you get 208.

3 0

3 years ago

Read 2 more answers

Find the maximum and minimum values of the objective function f(x, y) and for what values of x and y they occur, subject to the

Lady_Fox [76]

Given that f(x, y) is a linear function, and the constraints themselves are also linear, it follows that the vertices of the feasible region are the sites of extrema of f(x, y). So just find where each boundary line intersects with another line, and check the value of f(x, y) at each intersection.

We have

• x = 0 and y = 0 ===> (0, 0)

• x = 0 and 2x + 7y = 70 ===> y = 10 ===> (0, 10)

• y = 0 and 8x + 4y = 136 ===> x = 17 ===> (17, 0)

• 2x + 7y = 70 and 8x + 4y = 136 ===> (14, 6)

At these points, we respectively get

• f (0, 0) = 0

• f (0, 10) = 60

• f (17, 0) = 34

• f (14, 6) = 64

Then max f(x) = 64 at (14, 6) and min f(x) = 0 at (0, 0).

5 0

3 years ago