distance = speed * time
the first bus speed = x
second bus = x - 12
the sum of distance = 765 miles
first distance = 6x
second distance = 6 (x -12)
6x + 6(x-12) = 765
x + x -12 = 127.5
2x = 139.5
x = 69.75 mi/h which is the faster bus
the second bus speed = 57.75 mi/h
Here it is given that the width is x ft and total length of the fence is 2400 ft .
Let the length be y ft
So we have

Let A represents area, and area is the product of length and width .
So we get

Substituting the value of y, we will get

Second part
The area is maximum at the vertex, and vertex is

And

And that's the required dimensions .
Well what i got was 79.3 by finding the average by adding it all together then divided it by how many numbers
<span>the tens digit = n
</span><span>the units digit = n-5
n + n-5 = 9
2n = 9+5
2n = 14
n = 7 </span>← the tens digit
the units digit = n-5 = 7 - 5 = 2
<span>the number is 72</span>