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2 years ago

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hey, if y'all want any advice or help(ON ANYTHING), I'll always be here for you!! I like to help others out even when I need hel

p.

1 answer:

Marina86 [1]2 years ago

3 0

Answer:

I posted a question not too long ago, no one has answered yet and I'm almost done with the assignment, help would be greatly appreciated! :)

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Can someone help me

Slav-nsk [51]

9514 1404 393

Answer:

M = 7x² +21

Step-by-step explanation:

Subtract the unwanted terms on the left from both sides.

(-7x² +6x -16) + M = 6x +5

M = 6x +5 -(-7x² +6x -16)

M = 7x² +21 . . . . simplify

5 0

2 years ago

HELP ASAP (40 POINTS)

frez [133]

Answer:

c i think because the problem =-

$- \frac{1}{4}$

4 0

2 years ago

52 regular playing cards are randomly dealt to four players with each players receiving 13 cards. What is the probability that e

Vadim26 [7]

Answer:

The probability is 1/28,561

Step-by-step explanation:

Here, we want to find the probability that each of the players will receive exactly one ace.

In a deck of cards, we have 4 suites of 13 cards each, with each of the suites consisting of 1 ace.

So, the probability of getting an ace for each of the four players will be 4/52 = 1/13

Now, the probability of each of the players getting exactly one ace will be; first got one ace , second got one , third got one and fourth got one.

mathematically, this probability will be 1/13 * 1/13 * 1/13 * 1/13 = (1/13)^4 = 1/28,561

7 0

3 years ago

Please help me on this’ gracias

blondinia [14]

Answer:

9,4,-1,-6

Step-by-step explanation:

You just need to plug in the x values into the equation and solve.

6 0

2 years ago

Read 2 more answers

Find 2 common angles that sum to (17pi/12) 2. Evaluate tan(17pi/12) using the sum identity for tangent.

Dmitry [639]

Note that
$\frac{17 \pi }{12} = \frac{3 \pi }{12} + \frac{14 \pi }{12} = \frac{ \pi }{4} + \frac{7 \pi }{6}$

Note that
$x= \frac{ \pi }{4}:\,\, sin(x) =cos(x)= \frac{1}{ \sqrt{2} },\,tan(x)=1\\x= \frac{7 \pi }{6} :\,\,sin(x)=- \frac{1}{2} ,\,\,cos(x)=- \frac{ \sqrt{3} }{2} ,\,\,tan(x)= \frac{1}{ \sqrt{3} }$

Use the identity
$tan(x+y)= \frac{tan(x)+tan(y)}{1-tan(x)tan(y)}$

Therefore
$tan( \frac{17 \pi }{12} )= \frac{1+ \frac{1}{ \sqrt{3} } }{1- \frac{1}{ \sqrt{3} } } = \frac{ \sqrt{3}+1 }{ \sqrt{3}-1} = \frac{( \sqrt{3}+1 )^{2}}{( \sqrt{3}-1 )( \sqrt{3}+1 )} = \frac{3+1+2 \sqrt{3}}{3-1} =2+ \sqrt{3}$

Answer: 2 + √3

8 0

3 years ago