The distribution of X is X ~ N (20 , 6) and the probability that this American will receive no more than 24 Christmas cards this year is 0.7486.
<h3>Probability</h3>
a. Distribution
X ~ N (20 , 6)
b. P(x ≤24)
= P[(x - μ ) / σ (24 - 20) / 6]
= P(z ≤0.67)
= 0.74857
=0.7486
Hence:
Probability = 0.7486
c. P(21 < x < 26)
= P[(21 - 26)/ 6) < (x - μ ) / σ < (24 - 20) / 6) ]
= P(-0.83 < z < 0.67)
= P(z < 0.67) - P(z < -0.)
= 0.74857- 0.2033
= 0.54527
Hence:
Probability =0.54527
d. Using standard normal table ,
P(Z < z) = 66%
P(Z < 0.50) = 0.66
z = 0.50
Using z-score formula,
x = z× σ + μ
x = 0.50 × 6 + 20 = 23
23 Christmas cards
Therefore the distribution of X is X ~ N (20 , 6) and the probability that this American will receive no more than 24 Christmas cards this year is 0.7486.
Learn more about probability here:brainly.com/question/24756209
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Answer:
B=10
Step-by-step explanation:
It's a perfect square of equation ax²+2abx+b²
I'm the given equation a is 1 and b is 5 so 2(a)(b)=2(1)(5)=10
(ps: when I say b in the explanation I mean another b not the one in question as to not be confused)
Answer:
92 pounds
Step-by-step explanation:
Here is the complete question ;
4 people are going to a dinner party. Each person at the party will eat 23 pound of cake. If you can only buy whole pounds of cake, how many pounds should you buy?
total pounds to be bought = number of people at the party x total pounds they would eat
4 x 23 = 92 pounds
4.83
answer above answer above answer above
