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STatiana [176]
3 years ago
13

molecular formula citric acid2.A 10.0 mL sample of pineapple juice was titrated with 0.100 M sodium hydroxide solution. The aver

age volume of NaOH required to reach the endpoint was 12.8 mL. a.Calculate the number of moles of sodium hydroxide required to reach the endpoint. Show your work in equation editor. Remember to use units and report your answer to the proper number of significant figures.
Chemistry
1 answer:
Vika [28.1K]3 years ago
7 0

Answer: The number of moles of sodium hydroxide required to reach the endpoint is 0.00128

Explanation:

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution in ml}}      

Molarity of NaOH solution = 0.100 M

Volume of  NaOH  solution = 12.8 mL

Putting values in equation, we get:

0.100M=\frac{\text{Moles of}NaOH\times 1000}{12.8ml}\\\\\text{Moles of }NaOH=\frac{0.100mol/L\times 12.8}{1000}=0.00128mol

Thus the number of moles of sodium hydroxide required to reach the endpoint is 0.00128

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A compound is found to have a composition of 35.880% Cr, 21.076% P, and 43,545% O
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Explanation:

Cr=35.880/51=0.73≈0.7

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3 0
3 years ago
I really can’t do this don’t understand it
masya89 [10]

Answer:

7.96g, 33.79%

Explanation:

I'll try my best to explain the entire process behind this question ;)

From the question, you can write the reaction

2H_2O(l)->2H_2(g)+O_2(g)

Now, there are a few reasons it is like this. Oxygen is a diatomic element, meaning it doesn't and can't exist as just O. It exists as O₂. To balance, this, double the amount of water and hydrogen so there is an equal amount of  each element on both sides of the reaction (4 H's, 2 O's on the reactant side, and 4 H's, 2 O's on the product side).

From this we can get a mole-to-mole ratio.

Onto the stoichiometry. Our goal in this is to convert from grams of water to grams of hydrogen, and we do so with a mole to mole ratio.

71.0gH_2O*\frac{1molH_2O}{18.02g} *\frac{2molH_2}{2molH_2O}* \frac{2.02g}{1molH_2}\\\\ =7.96gH_2

Basically, what I did was divide by water's molar mass to get moles of water, multiplied by the mole-to-mole ratio (2:2) to get moles of H2, and then multiplied by H2's molar mass to get what should be the amount of H2 produced by the reaction.

For percent yield, you can calculate it is such:

\frac{Actual}{Theoretical}*100

Plug the numbers in:

\frac{2.69g}{7.96g}*100\\\\ =33.79%

So, the percent yield is 33.79%

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Why ddo all collisions between reactant molecules not lead to reaction.
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Answer:

The colliding molecules need to possess certain energy which is greater than the activation energy Ea and proper orientation.

<h3>Not all collisions result in a chemical reaction because not all collisions have the have sufficient amount of energy or have the appropriate activation energy. Nor do they all have this correct orientation. Molecules need to collide in such a way that they're oriented, so the correct bonds could break in. The correct bonds conform. And then, of course, they need to have sufficient activation energy in order to initiate the breaking of the bonds.</h3>

<h3>Hope this helps please let me know If I'm wrong.</h3>
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