A compound is found to have a composition of 35.880% Cr, 21.076% P, and 43,545% O
1 answer:
Explanation:
Cr=35.880/51=0.73≈0.7
P=21.076/31=0.67≈0.7
O=43.543/16=2.71
Divide each by 0.7 u get
Cr=1 ,P =1, O=4
Empirical formula is CrPO4
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