What is ionisation enthalpy?
2 answers:
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The [OH⁻] of the solution is 5.37×10⁵ M.
<h3 /><h3>What is pOH?</h3>This is the negative logarithm to base 10 of hydroxy ion [OH⁻] concentration.
To calculate the hydroxy ion [OH⁻] concentration we use the formula below.
Note:
- pH+pOH = 14
- pOH = 14-pH
- pOH = 14-9.77
- pOH = 4.27
Formula:
- [OH⁻] = 1/
................. Equation 1
Given:
- pOH = 4.27
Substitute the value into equation 1
- [OH⁻] = 1/
- [OH⁻] = 5.37×10⁵
Hence, The [OH⁻] of the solution is 5.37×10⁵ M.
Learn more about hydroxy ion concentration here: brainly.com/question/17090407