It's shifted left 2 units and down 5 units.
To find the point on the graph of g, we use the horizontal shift for the x-coordinate 4 to get 4–2=2, and the vertical shift for the y-coordinate –3 to get –3–5=–8.
are you in algebra 1? i have trouble on this to, try simplifying both sides of the equation as best as you can, maybe that could help
Do you mean a_(n+1), worded a sub (n+1)?
If so yes. If the function of the sequence is getting smaller or more negative with each term.
Answer:
plot the points (0, 2) and (π, 4)
Step-by-step explanation:
To use your sine plotting tool, you need two points on the graph. The midline point is given for you. It is the y-intercept, (0, 2).
The maximum amplitude point is 1/4 of a period from this midline point. The frequency is 1/(4π), and the period is the inverse of frequency:
T = 1/f = 4π
So, 1/4 of a period is ...
T/4 = (4π)/4 = π
The peak value of the function is the amplitude added to the midline, so is 2+2 = 4.
The second point you need to plot is the peak value, (π, 4).
Your points are (0, 2) and (π, 4).
First do 43 - 30= $13 for two hats
so for one hat you do 13 divided by 2 which equals= <u>$6.50</u> for one hat
then you do 30 - 13= $17 for two pairs of gloves
so for one pair of gloves you do 17 divided by 2=<u> $8.50</u> for one pair of gloves