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3 years ago

Points for you........................................

Mathematics

2 answers:

Anni [7]3 years ago

8 0

Answer:

Thanks man..............

Ilya [14]3 years ago

3 0

Answer:

thx

Step-by-step explanation:

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Vitek1552 [10]

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Blood enters the heart through two large veins, the inferior and superior vena cava, emptying oxygen-poor blood from the body into the right atrium.

Step-by-step explanation:

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3 years ago

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vlada-n [284]

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3 years ago

Oliver invested $970 in an account paying an interest rate of 7 1/2 % compounded continuously. Carson invested $970 in an accoun

hjlf

Answer:

0.50 or about half a year longer.

Step-by-step explanation:

We can write an equation to model bot investments.

Oliver invested $970 in an account paying an interest rate of 7.5% compounded continuously.

Recall that continuous compound is given by the equation:

$A = Pe^{rt}$

Where A is the amount afterwards, P is the principal amount, r is the rate, and t is the time in years.

Since the initial investment is $970 at a rate of 7.5%:

$A = 970e^{0.075t}$

Carson invested $970 in an account paying an interest rate of 7.375% compounded annually.

Recall that compound interest is given by the equation:

$\displaystyle A = P\left(1+\frac{r}{n}\right)^{nt}$

Where A is the amount afterwards, P is the principal amount, r is the rate, n is the number of times compounded per year, and t is the time in years.

Since the initial investment is $970 at a rate of 7.375% compounded annually:

$\displaystyle A = 970\left(1+\frac{0.07375}{1}\right)^{(1)t}=970(1.07375)^t$

When Oliver's money doubles, he will have $1,940 afterwards. Hence:

$1940= 970e^{0.075t}$

Solve for t:

$\displaystyle 2 = e^{0.075t}$

Take the natural log of both sides:

$\ln\left (2\right) = \ln\left(e^{0.075t}\right)$

Simplify:

$\ln(2) = 0.075t\Rightarrow \displaystyle t = \frac{\ln(2)}{0.075}\text{ years}$

When Carson's money doubles, he will have $1,940 afterwards. Hence:

$\displaystyle 1940=970(1.07375)^t$

Solve for t:

$2=(1.07375)^t$

Take the natural log of both sides:

$\ln(2)=\ln\left((1.07375)^t\right)$

Simplify:

$\ln(2)=t\ln\left((1.07375)\right)$

Hence:

$\displaystyle t = \frac{\ln(2)}{\ln(1.07375)}$

Then it will take Carson's money:

$\displaystyle \Delta t = \frac{\ln(2)}{\ln(1.07375)}-\frac{\ln(2)}{0.075}=0.4991\approx 0.50$

About 0.50 or half a year longer to double than Oliver's money.

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What is the answer to this problem?

zepelin [54]

Answer:

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You subtract 180 from 56 then add your answer, 124 to 20, then subtract 144 from 180 to get 36

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A digital rain gauge has an outdoor sensor that collects rainfall and transmits data to an indoor display. Assume you produced a

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A digital rain gauge has an outdoor sensor that collects rainfall and transmits data to an indoor display. Assume you produced a graph of all the data collected by the rain gauge over a 24-hour period. a. Would that graph be a discrete graph or a continuous graph? Explain your reasoning. b. b. Describe the general shape of the graph assuming it rained at a rate of 0.1 inch per hour for the entire 24-hour period. c. c. Describe the general shape of the graph assuming it rained 0.1 inch per hour for 6 hours, stopped raining for 6 hours, and then rained 0.2 inch for 12 hours.

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