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iren2701 [21]
2 years ago
14

Multiply -9/8 by -14/15

Mathematics
2 answers:
Fittoniya [83]2 years ago
4 0

Answer:

1.05

Step-by-step explanation:

Leto [7]2 years ago
3 0

Answer:

1.05 is the answer

Step-by-step explanation:

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A population has the following characteristics. (a) A total of 75% of the population survives the first year. Of that 75%, 25% s
Artemon [7]

Answer:

= \left[\begin{array}{ccc}1344\\84\\28\end{array}\right]  \left \begin{array}{ccc}{0 \  \leq  age   \leq  1 }\\{ 1 \  \leq  age   \leq  2 }\\{2 \  \leq  age  \leq 3}\end{array}\right

i.e after the first year ;

there 1344 members in the first age class

84 members for the second age class; and

28 members for the third age class

Step-by-step explanation:

We can deduce that the age distribution vector x represents the number of population members for each age class; Given that in each class of age there are 112 members present.

The current age distribution vector is as follows:

x = \left[\begin{array}{ccc}1&1&2\\1&1&2\\1&1&2\end{array}\right] \left[\begin{array}{ccc}{0 \  \leq  age   \leq  1 }\\{ 0 \  \leq  age   \leq  2 }\\{0 \  \leq  age   \leq 3}\end{array}\right]

Also , the age transition matrix is as follows:

L = \left[\begin{array}{ccc}3&6&3\\0.75&0&0 \\0&0.25&0\end{array}\right]

After 1 year ; the age distribution vector will be :

x_2 =Lx_1 = \left[\begin{array}{ccc}3&6&3\\0.75&0&0 \\0&0.25&0\end{array}\right]  \left[\begin{array}{ccc}1&1&2\\1&1&2\\1&1&2\end{array}\right]

= \left[\begin{array}{ccc}1344\\84\\28\end{array}\right]  \left \begin{array}{ccc}{0 \  \leq  age   \leq 1 }\\{ 1 \  \leq  age   \leq  2 }\\{2 \  \leq  age   \leq  3}\end{array}\right

6 0
3 years ago
PLZ HELP WILL GIVE BRAINLIEST WORTH 10 PTS THX!!
antiseptic1488 [7]

Answer:

  64/49

Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)^c = a^(bc)

  (a^b)(a^c) = a^(b+c)

  a^-b = 1/a^b

  a^0 = 1

_____

Using these rules, we can simplify the given expression to ...

  \left(\dfrac{8\cdot 4\cdot 2}{8\cdot 7}\right)^2\times\left(\dfrac{8^0}{7^{-3}}\right)^3\times 7^{-9}\\\\=\dfrac{8^2}{7^2}\times(8^{0\cdot 3}\cdot 7^{3\cdot 3})\times 7^{-9}\\\\=\dfrac{64}{49}\times(8^07^{9-9})=\boxed{\dfrac{64}{49}}

6 0
3 years ago
Read 2 more answers
The exact numbers of each color of Umbrella Corporation's most popular candy, W&Ws, naturally vary from bag to bag, but the
sattari [20]

Question in order:

The exact numbers of each color of Umbrella Corporation's most popular candy, W&Ws, naturally vary from bag to bag, but the company wants to make sure that the process as a whole is producing the five colors in equal proportions. Which of the following would represent the alternative hypothesis in a chi-squared goodness-of-fit test conducted to determine if the five colors of W&Ws occur in equal proportions?

a. H1: All of the proportions are different from 0.20

b. HI: p1 = P2 = p3 =P4=p5 = 0.20

c. H1: At least one proportion is not equal to 0.20

d. H1: At least two of the mean number of colors differ from one another.

e. HI: the number of candies per bag and candy color are dependent

Answer:

option C

Step-by-step explanation:

H1: At least one proportion is not equal to 0.20

6 0
3 years ago
A six-sided die is loaded in such a way that the probability of each face turning up is proportional to the number of dots on th
agasfer [191]

Answer:

P(2U5) = 7/21 = 1/3

the probability of getting either a 5 or a 2 in one throw is 1/3

Step-by-step explanation:

Given that; the probability of each face turning up is proportional to the number of dots on that face

P(1) = 1×P(1)

P(2) = 2×P(1)

P(3) = 3×P(1)

P(4) = 4×P(1)

P(5) = 5×P(1)

P(6) = 6×P(1)

P(T) = 21×P(1)

Where;

P(x) is the probability of getting number x on the dice.

P(T) is the total probability of obtaining any number

N(x) is the number of possible number x in terms of the distribution function.

P(x) = N(x)/N(T) ....1

And since P(T) is constant, and P(T) is proportional to N(T) then,

P(x) is directly proportional to N(x)

So, equation 1 becomes;

P(x) = N(x)/N(T) = P(x)/P(T) ....2

The probability of getting either a 5 or a 2 in one throw

P(2U5) = (P(2) + P(5))/P(T)

Substituting the values of each probability;

P(2U5) = (2P(1) + 5P(1))/21P(1)

P(2U5) = 7P(1)/21P(1)

P(1) cancel out, to give;

P(2U5) = 7/21 = 1/3

the probability of getting either a 5 or a 2 in one throw is 1/3

8 0
3 years ago
A veterinarian is changing the diets of two animals, Simba and Cuddles. Simba currently consumes 1,520 Calories per day. That nu
kykrilka [37]

Answer:

6 days ; 2300 calories

Step-by-step explanation:

Given the following :

Current consumption :

Simba = 1520 calories per day

Increases by 130 calories per day : After d days ;

S(d) = 1520 + 130d

Where ; d = number of days

Cuddle = 3380 calories

Decreases by 180 calories each day; after d days ;

S(d) = 3380 - 180d

Pattern continues until they both consume same number of calories each day

S(d) = C(d)

1520 + 130d = 3380 - 180d

130d + 180d = 3380 - 1520

310d = 1860

d = 6

Number of calories they will be consuming them ;

Using : S(d) = 3380 - 180d

S(6) = 3380 - 180(6)

S = 3380 - 1080

S = 2300

They will be consuming 2300 calories by then.

8 0
3 years ago
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