Hey!
Hope this helps...
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x + y = 3
x = 3 - y
y = 2x - 15
y = 2(3 - y) - 15
y = 6 - 2y - 15
y = -2y - 9
3y = -9
y = -3
y = 2x - 15
-3 = 2x - 15
-2x = -12
x = 6
So...
The answer is: (6, -3)
∠СXA = ∠BXA + ∠СXB = 30°20' + 40°35' = 70°55'
The answer is C.
90/105=6/7
Hope this helps!
Please, see the offered decision:
1) common equation for lines is y=kx+b. If k₁=k₂ (for line 1 and line 2) ⇒ 'line 1' || 'line 2'.
2) for line 3x+5y=6 k= -3/5. It means (according to item 1) for unknown line k is the same (-3/5).
3) using points (0;3) it is easy to find parameter b (x=0, y=3) via y=kx+b:
3=0*(-3/5)+b ⇔ b=3.
4) finaly (k=-3/5; b=3):
-5 is for f(x)=x+5
4 is for g(x)=x-4
Hope this helps!!