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Anastasy [175]
3 years ago
11

Answer the following questions:

Mathematics
1 answer:
Lelechka [254]3 years ago
5 0

Answer:

a. RTP

b. NM

c. x = 7

3x - 1 = 20

3x = 21

x = 7

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Each week, Heather’s company has $5000 in fixed costs plus an additional $250 for each system produced. The company is able to p
kvv77 [185]

The question is an illustration of composite functions.

  • Functions c(n) and h(n) are \mathbf{c(n) = 5000 + 250n} and \mathbf{n(h) = 5h}
  • The composite function c(n(h)) is \mathbf{c(n(h)) = 5000 + 1250h}
  • The value of c(n(100)) is \mathbf{c(n(100)) = 130000}
  • The interpretation is: <em>"the cost of working for 100 hours is $130000"</em>

The given parameters are:

  • $5000 in fixed costs plus an additional $250
  • 5 systems in one hour of production

<u>(a) Functions c(n) and n(h)</u>

Let the number of system be n, and h be the number of hours

So, the cost function (c(n)) is:

\mathbf{c(n) = Fixed + Additional \times n}

This gives

\mathbf{c(n) = 5000 + 250 \times n}

\mathbf{c(n) = 5000 + 250n}

The function for number of systems is:

\mathbf{n(h) = 5 \times h}

\mathbf{n(h) = 5h}

<u>(b) Function c(n(h))</u>

In (a), we have:

\mathbf{c(n) = 5000 + 250n}

\mathbf{n(h) = 5h}

Substitute n(h) for n in \mathbf{c(n) = 5000 + 250n}

\mathbf{c(n(h)) = 5000 + 250n(h)}

Substitute \mathbf{n(h) = 5h}

\mathbf{c(n(h)) = 5000 + 250 \times 5h}

\mathbf{c(n(h)) = 5000 + 1250h}

<u>(c) Find c(n(100))</u>

c(n(100)) means that h = 100.

So, we have:

\mathbf{c(n(100)) = 5000 + 1250 \times 100}

\mathbf{c(n(100)) = 5000 + 125000}

\mathbf{c(n(100)) = 130000}

<u>(d) Interpret (c)</u>

In (c), we have: \mathbf{c(n(100)) = 130000}

It means that:

The cost of working for 100 hours is $130000

Read more about composite functions at:

brainly.com/question/10830110

5 0
3 years ago
A collection of coins nickels and quarters is worth $1.25 . There are 13 coins in all. How many of each are there?
yulyashka [42]
3 quarters (75cents) and 10 nickels (50cents) = 1.25$
7 0
3 years ago
What is the arithmetic sequence of -1.2, 0.6 , 1.8 , 3.0​
zlopas [31]

-1.2 ( a negative number is always smaller than positive number)

0.6

1.8

3.0

4 0
3 years ago
The number of popcorns sold at a movie theatre was 8 less than three times the number hotdogs. How many hotdogs did the theatre
serg [7]

Answer:

  200

Step-by-step explanation:

If the theater sold 8 more popcorns, the total would be 600, and it would be exactly 3 times the number of hotdogs. The theater sold 1/3 of 600, or 200 hotdogs.

6 0
3 years ago
How do you solve this: In ?PQR, PQ = 39 cm and PN is an altitude. Find PR if QN = 36 cm and RN = 8 cm.
ikadub [295]

Answer:

PR = 17 cm


Step-by-step explanation:

Given  :

In ΔPQR,

PQ = 39 cm

PN is an altitude.

QN = 36 cm

RN = 8 cm.

To Find : Length of PR

Solution :

Since we are given that PN is an altitude .

So, PN divides ΔPQR in two right angled triangles named as ΔPQN and ΔPRN. (Refer attached file)

So, first we find Length of PN in ΔPQN using Pythagoras theorem i.e.

(Hypotenuse)^{2}=(Perpendicular)^{2} +(Base)^{2}

(PQ)^{2}=(PN)^{2} +(QN)^{2}

(39)^{2}=(PN)^{2} +(36)^{2}

1521=(PN)^{2} +1296

1521 -1296=(PN)^{2}

225=(PN)^{2}

\sqrt{225} = PN

15 = PN

Thus, Length of PN = 15cm

Now to find length of PR we will use Pythagoras theorem in ΔPRN.

(PR)^{2}=(PN)^{2} +(NR)^{2}

(PR)^{2}=(15)^{2} +(8)^{2}

(PR)^{2}=225 +64

(PR)^{2}=289

PR= \sqrt{289}

PR= 17

Hence the length of PR = 17 cm



3 0
3 years ago
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