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2 years ago

Convert the following angle from degrees to radians. Express your answer in simplest

Mathematics

1 answer:

Zigmanuir [339]2 years ago

8 0

(150*pi)/180= 2.617 radians

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Whats equivalent to 11 to the 8th power over 11 to the 3rd power

arsen [322]

I did it wrong the first time you're answer is b. 11*11^4

3 0

2 years ago

Any answers I need help

natulia [17]

Answer:

(A) 21

Step-by-step explanation:

5x-15 needs to equal 90 since it is a right angle and 21 makes that true

$(5*21)=105\\105-15=90$

6 0

1 year ago

Read 2 more answers

If you earned 892.50 after depositing 1400 at 4.25% simple interest, how long was it invested ? Using the simple interest formul

DanielleElmas [232]

Answer:

Time t = 15 years

Step-by-step explanation:

Interest = 892.50

Principal = 1400

Rate = 4.25%

Time = unknown

But

interest I = Principal p * rate r * time t

Time t = interest I/(principal P * rate r)

Time t=( 892.50*100)/(1400*4.25)

Time t=89250/5950

Time t = 15 years

4 0

2 years ago

If a 1- foot string has a fundamental frequency of 100cps, how long would the string have to be so it would have a frequency of

Gala2k [10]

The string would have to be 4 feet long to have a frequency of 400cps because each foot=100cps

8 0

2 years ago

The revenue R you receive for selling pizza slices depends on the price p that you charge per slice and is modeled by R =-16p

sp2606 [1]

Answer:

$p \geq 0$

Step-by-step explanation:

Given

$R(p) = -16p^2 + 80p + 5$

Required

Determine the domain of the function

To do this, we need to solve for the vertex, p of the function

$p= \frac{-b}{2a}$

Given the the general form of a quadratic function is:

$y = ax^2 + bx + c$

By comparison, we have:

$a = -16$ $b =80$ $c = 5$

So:

$p= \frac{-b}{2a}$

$p = \frac{-80}{-16 * 5}$

$p = \frac{-80}{-80}$

$p = 1$

Substitute 1 for p in $R(p) = -16p^2 + 80p + 5$

$R(1) = -16(1)^2 + 80(1) + 5$

$R(1) = -16 + 80 + 5$

$R(1) = 69$

This implies that

$(p, R) = (1,69)$

The interpretation of this is that;

<em>For every value of p, there's a corresponding value of R.</em>

<em>However, because p indicates price and it's impossible to have a negative price, we can say that the minimum value of p is 0;</em>

Hence, the domain is

$p \geq 0$

8 0

2 years ago