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katrin2010 [14]
3 years ago
9

The student council had a cupcake fundraiser. The cupcakes were donated, but the icing, plates and candy were purchased for $50.

The
student council sold the cupcakes for $1.50 each.
Which equation shows the relationship between the profit, p, and the number of cupcakes sold, n?
Mathematics
1 answer:
Marizza181 [45]3 years ago
7 0
1.50n - 50 = p

Explanation: 1.50n = profits from selling cupcakes. Subtract from cost to make cupcakes (50) to find profit.
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Answer:

9.9 years

Step-by-step explanation:

A = P e ^(rt)

Where A is the amount in the account

P is the amount invested

R is the interest rate

t is the time

P = 8500

r =7% = .07

A = 17000

Substituting into the equation

17000=8500 e^(.07t)

Divide each side by 8500

17000/8500=8500/8500 e^(.07t)

2 = e^(.07t)

Take the natural log of each side

ln (2) = ln e^(.07t)

ln(2) = .07t

Divide each side by .07

ln(2)/.07 = .07t/.07

ln(2)/.07 = t

9.902102579=t

Rounding to one decimal place

9.9 years

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Here's your answer!

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Answer:

\large\boxed{\bold{NO\ REAL\ SOLUTIONS}}\\\boxed{x=4-2i,\ x=4+2i}

Step-by-step explanation:

Domain:\\c-4\neq0\ \wedge\ c-5\neq0\Rightarrow c\neq4\ \wedge\ c\neq5\\\\\dfrac{c}{c-5}=\dfrac{4}{c-4}\qquad\text{cross multiply}\\\\c(c-4)=4(c-5)\qquad\text{use the distributive property}\\\\c^2-4c=4c-20\qquad\text{subtract}\ 4c\ \text{from both sides}\\\\c^2-8c=-20\qquad\text{add 20 to both sides}\\\\c^2-8c+20=0\qquad\text{use the quadratic formula}

\text{for}\ ax^2+bx+c=0\\\\\text{if}\ b^2-4ac0,\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

x^2-8x+20=0\\\\a=1,\ b=-8,\ c=20\\\\b^2-4ac=(-8)^2-4(1)(20)=64-80=-16

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