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EleoNora [17]
3 years ago
13

There are 40 GT students going on a field trip. Each one pays their teacher $8.75 to cover admission to the museum and lunch. Ad

mission for the students is $120 and each one gets an equal amount to spend on lunch. How much will each GT student be able to spend on lunch?
Mathematics
1 answer:
Norma-Jean [14]3 years ago
3 0

Step-by-step explanation:

There are 40 DuBois students going on a field trip.

Each one pays their teacher $8.75 to cover admission to the museum and lunch.

Admission for the students is $120 and each one gets an equal amount to spend on lunch.

To Find :

How much will each DuBois student be able to spend on lunch.

Solution :

Amount they paid for admission :

\begin{gathered}P =\$ \dfrac{120}{40}\\\\P=\$3\end{gathered}P=$40120P=$3

Now, amount of money to spend on lunch is 8.75 -8.75−3 = $5.75 .

Hence, this is the required solution.

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zhuklara [117]
Oh this is simple. If there are 35 people and 3,430 seedlings and its evenly distributed, all you have to do is divide 3,430 by 35 which is 98 seedlings each.

In equation its this:  
3,430/35=98 
5 0
3 years ago
It costs $3.45 to buy 34 lb of chopped walnuts. How much would it cost to purchase 7.5 lbs of walnuts? GIVING BRAINLIEST *URGENT
lesantik [10]

<u>Answer:</u>

$0.75

<u>Step-by-step explanation:</u>

$3.45 ÷ 34 lb. = $0.10 per pound (rounded)

$0.10 x 7.5 = $0.75

It would cost $0.75 to buy 7.5 lbs of chopped walnuts

<em>I'm sorry if wrong! You are loved and you are beautiful/handsome!</em>

-Bee

7 0
3 years ago
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A kitchen floor has 15 1/2 tiles in an area of 2 3/5 square feet. How many tiles are in one square foot?
serg [7]
Your answer would be 5 25/26
5 0
3 years ago
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Find the interquartile range for a data set having the five-number summary: 3.4, 10.8, 16.7, 23.1, 31.5
natita [175]

.Answer:

D. 12.3

Step-by-step explanation:

Arrange the data in increasing order

3.4, 10.8, 16.7, 23.1, 31.5

⇒This is an odd set of numbers, to find the interquartile range you include the median in both quartiles.

Locate the median/center value

3.4, 10.8, 16.7, 23.1, 31.5

Find lower half and find the median

lower half values⇒3.4, 10.8, 16.7

Median=Q1=10.8

Find the upper half and find

upper half= 16.7,23.1, 31.5

median= 16.7,23.1,31.5

Q3=23.1

Interquartile range=Q3-Q1

23.1-10.8=12.3

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3 years ago
Anyone able to help?
harkovskaia [24]

Answer:

Technically he isn't, but he is off by only 0.5 cm.

Step-by-step explanation:

To check, we can use pythagorean theorem:

22.8^2 + 13.82^2 = about 22.6

However, Mr. Lim got it as around 26.1

5 0
2 years ago
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