1.name two streets that intersect but do not appear to be perpendicular
2 answers:
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Answer:
Length of the rectangle is 15.0325 km and width is 0.3765 km.
Explanation:
Given:
Perimeter of a rectangle = 30.8 km
Length of diagonal of rectangle = 11 km
To find:
The length and width of rectangle=?
Solution:
Lets assume length of the rectangle = x km
And assume width of the rectangle = y km
Lets first create equation using given perimeter
perimeter of rectangle = 2 ( length + width )
=> 30.8 km = 2 ( x + y )
=>
=> y = 15.4 – x ------(1)
As diagonal and two sides of rectangle forms right angle triangle whose hypoteneus is diagonal ,
=>
=>
=>
On substituting value of y from (1) in above equation we get
=>
=>
=>
=>
Solving above quadratic equation using quadratic formula
General form of quadratic equation is
And quadratic formula for getting roots of quadratic equation is
As equation is , in our case
a = 2 , b = -30.8 and c = 116.16
Calculating roots of the equation we get
=> x = 15.0325 or x = 0.3675
As generally length is longer one ,
So x = 1.0325
From equation (1) y = 15.4 – x = 0.3765
Hence length of the rectangle is 15.0325 km and width is 0.3765 km.
Answer:
1. 12 inches are in 1 foot, 48 inches of ribbon divided by 12 is 4 feet of ribbon.
2. Since there are 12 inches in 1 foot you multiply by 3 to 12 inches for 36 inches of ribbon.
3. When you're finding inches you need to divide but when you're finding feet you need to multiply.
4. His library card is 80 millimeters and since there are 10 millimeters in 1 centimeter you divide 80 by 10 to get 8 centimeters
5. His key chain is 35 millimeters long.
6. 3 quarts is bigger than 5 pints by 2 cups.
Picture contains the work you should show for questions 5 and 6.
