Because it's a multiplication, we can choose this:
72=8x9
The percentage of the runners who have times less than 14.4 sec is 0.15%
The times of all 15-year old who run a certain race are approximately normally distributed with a given mean of 18 sec and a standard deviation of 1.2 sec.
We know that,
where,
X = raw score = 14.4
μ = mean = 18
σ = standard deviation = 1.2
Putting the values,
Finding the probability from the z score table, we get
P(z < -3) = 0.00135 = 0.135%
Disclaimer: The question is incomplete. Please read below to find the missing content.
Question: The times of all 15-year-olds who run a certain race are approximately normally distributed with a given mean of 026-1 = 18 seconds and a standard deviation of 026-2. = 1.2 sec. What percentage of the runners have times less than 14.4 seconds?
0.15%
0.15%
0.30%
0.60%
2.50%
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Answer:
V= 160pi or V= 502.65
Step-by-step explanation:
V = pi × r^2 × h
V = pi × (4)^2 × 10
V = pi × 16 × 10
V= 160pi or V = 502.65
Given:
The two points on a coordinate plane are C(-5,-1) and D(0,3).
To find:
The distance between C and D.
Solution:
Distance formula:
Using the distance formula, the distance between C(-5,-1) and D(0,3) is
On further simplification, we get
Therefore, the distance between C and D is 6.40 units.
