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Georgia [21]
3 years ago
10

Write a quadratic function that has been translated 1 units to the right and 3 units down.

Mathematics
1 answer:
vodka [1.7K]3 years ago
6 0

Step-by-step explanation:

Hi,

f(x) = (x - 1) - 3

The -1 is the 1 unit to the right (even though it's being subtracted, it's going to the right because it's embedded with the x)

And the -3 is not embedded with the x, meaning the function will move 3 units down.

I hope this helps :)

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Because it's a multiplication, we can choose this:

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5 0
3 years ago
the times of all 15 year olds who run a certain race are approximately normally distributed with a given mean
Butoxors [25]

The percentage of the runners who have times less than 14.4 sec is  0.15%

The times of all 15-year old who run a certain race are approximately normally distributed with a given mean of 18 sec and a standard deviation of 1.2 sec.

We know that,

where,

X = raw score = 14.4

μ = mean = 18

σ = standard deviation = 1.2

Putting the values,

Finding the probability from the z score table, we get

P(z < -3) = 0.00135 = 0.135%

Disclaimer: The question is incomplete. Please read below to find the missing content.

Question: The times of all 15-year-olds who run a certain race are approximately normally distributed with a given mean of 026-1 = 18 seconds and a standard deviation of 026-2. = 1.2 sec. What percentage of the runners have times less than 14.4 seconds?

0.15%

0.15%

0.30%

0.60%

2.50%

Learn more about percentages here brainly.com/question/809966

#SPJ4

8 0
2 years ago
Find the volume of the cylinder.
disa [49]

Answer:

V= 160pi or V= 502.65

Step-by-step explanation:

V = pi × r^2 × h

V = pi × (4)^2 × 10

V = pi × 16 × 10

V= 160pi or V = 502.65

7 0
3 years ago
What is the distance (in units) between points C and D? Round your answer to the nearest hundredth.
r-ruslan [8.4K]

Given:

The two points on a coordinate plane are C(-5,-1) and D(0,3).

To find:

The distance between C and D.

Solution:

Distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using the distance formula, the distance between C(-5,-1) and D(0,3) is

CD=\sqrt{(0-(-5))^2+(3-(-1))^2}

CD=\sqrt{(0+5)^2+(3+1)^2}

CD=\sqrt{(5)^2+(4)^2}

CD=\sqrt{25+16}

On further simplification, we get

CD=\sqrt{41}

CD=6.40312424

CD\approx 6.40

Therefore, the distance between C and D is 6.40 units.

6 0
3 years ago
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