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3 years ago

What is the solution of x=2+\sqrt(x-2) x = 2 x = 3 x = 2 or x = 3 no solution

2 answers:

5 0

$D:x\geq2\\\\
x=2+\sqrt{x-2}\\
\sqrt{x-2}=x-2\\
x-2=x^2-4x+4\\
x^2-5x+6=0\\
x^2+x-6x+6=0\\
x^2-2x-3x+6=0\\
x(x-2)-3(x-2)=0\\
(x-3)(x-2)=0\\
x=3 \vee x=2$

natta225 [31]3 years ago

4 0

Answer:

The solution is x = 2 or x = 3

Step-by-step explanation:

we have to find the solution of the equation

$x=2+\sqrt{(x-2)}$

$x=2+\sqrt{(x-2)}\\ \\x-2=\sqrt{x-2}\\\\\text{Squaring on both sides }\\\\(x-2)^2=x-2\\\\x^2+4-4x=x-2\\\\x^2-5x+6=0\\\\x^2-2x-3x+6=0\\\\x(x-2)-3(x-2)=0\\\\(x-2)(x-3)=0\\\\x=2\text{ or }x=3$

Hence, correct option is x = 2 or x = 3

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If Lebron can run 12 laps in 2 hours, approximately how long will it take him to run 60 laps?

ddd [48]

Answer:

10 hours

Step-by-step explanation:

Let's set up a proportion using the following setup.

hours/laps=hours/laps

We know that it takes him 2 hours to run 12 laps. We don't know how long it will take him to run 60 laps, so we can say it takes x hours to run 60 laps.

2 hours/12 laps=x hours/60 laps

2/12=x/60

We want to find out what x is. In order to do this, we have to get x by itself. Perform the opposite of what is being done to the equation. Keep in mind, everything done to one side, has to be done to the other.

x is being divided by 60. The opposite of division is multiplication, so multiply both sides by 60.

60*2/12=x/60*60

60*2/12=x

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It will take Lebron 10 hours to run 60 laps.

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3 years ago

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Step-by-step explanation:

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3 years ago

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OverLord2011 [107]

To figure this equation out, you'll have to divide 39 by 52% (0,52)

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3 years ago

Read 2 more answers

Prove or disprove (from i=0 to n) sum([2i]^4) <= (4n)^4. If true use induction, else give the smallest value of n that it doe

ddd [48]

Answer:

The statement is true for every n between 0 and 77 and it is false for $n\geq 78$

Step-by-step explanation:

First, observe that, for n=0 and n=1 the statement is true:

For n=0: $\sum^{n}_{i=0} (2i)^4=0 \leq 0=(4n)^4$

For n=1: $\sum^{n}_{i=0} (2i)^4=16 \leq 256=(4n)^4$

From this point we will assume that $n\geq 2$

As we can see, $\sum^{n}_{i=0} (2i)^4=\sum^{n}_{i=0} 16i^4=16\sum^{n}_{i=0} i^4$ and $(4n)^4=256n^4$ . Then,

$\sum^{n}_{i=0} (2i)^4 \leq(4n)^4 \iff \sum^{n}_{i=0} i^4 \leq 16n^4$

Now, we will use the formula for the sum of the first 4th powers:

$\sum^{n}_{i=0} i^4=\frac{n^5}{5} +\frac{n^4}{2} +\frac{n^3}{3}-\frac{n}{30}=\frac{6n^5+15n^4+10n^3-n}{30}$

Therefore:

$\sum^{n}_{i=0} i^4 \leq 16n^4 \iff \frac{6n^5+15n^4+10n^3-n}{30} \leq 16n^4 \\\\ \iff 6n^5+10n^3-n \leq 465n^4 \iff 465n^4-6n^5-10n^3+n\geq 0$

and, because $n \geq 0$ ,

$465n^4-6n^5-10n^3+n\geq 0 \iff n(465n^3-6n^4-10n^2+1)\geq 0 \\\iff 465n^3-6n^4-10n^2+1\geq 0 \iff 465n^3-6n^4-10n^2\geq -1\\\iff n^2(465n-6n^2-10)\geq -1$