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Anettt [7]
3 years ago
11

You are working as a caterer and need 20 gallons of lemonade for an upcoming event. The bottles of lemonade you are purchasing a

re in liters. How many liters will you need to equal 20 gallons of lemonade? Round your answer to the nearest tenth of a liter.
Mathematics
1 answer:
miskamm [114]3 years ago
6 0
It should be 76!!!!!!!!!
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HELP PLEASE ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!11111
vaieri [72.5K]

Answer:

16(0.5x - 0.75y + 2)

Step-by-step explanation:

16 x 0.5 = 8

16 x -0.75 = -12

16 x 2 = 32

4 0
2 years ago
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Complete the description of what happens to a figure when the given sequence of transformations is applied to it: (x,y) -> (-
RoseWind [281]
Omg I wish I could help I am not in this top level ‍♂️
5 0
3 years ago
A certain forest covers an area of
iVinArrow [24]

Answer:

2598 square kilometers

Step-by-step explanation:

Hello

Step 1

year one

using a rule of three is possible to find how much is 8.75 od 4500 km2

Let

if

4500 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

4500:100\\x:8.75\\\frac{4500}{100}=\frac{x}{8.75}\\x=\frac{4500*8.75}{100} \\x=393.75\\

at the end of the year one, the area will be

4500-393.75=4106.25

this will be the initial area for the year 2.

Step 2

repite the step 1 with area initial =4106.25 km2

4106.25 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

4106.25:100\\x:8.75\\\frac{4106.25}{100}=\frac{x}{8.75}\\x=\frac{4106.25*8.75}{100} \\x=359.29\\

at the end of the year 2, the area will be

4106-359.29=3746.70

this will be the initial area for the year 3.

Step 3

repite the step 1 with area initial =4106.25 km2

3746.70 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

3746.70:100\\x:8.75\\\frac{3746.70}{100}=\frac{x}{8.75}\\x=\frac{3746.7*8.75}{100} \\x=327.83\\

at the end of the year 3, the area will be

3746.70-327.83=3419.09

this will be the initial area for the year  4.

Step 4

year four

repite the step 1 with area initial =3419.09 km2

3419.09 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

3419.09:100\\x:8.75\\\frac{3419.09}{100}=\frac{x}{8.75}\\x=\frac{3419.09*8.75}{100} \\x=299.17\\

at the end of the year 4, the area will be

3419.09-299.173=3119.82

this will be the initial area for the year  5.

Step 5

year five

repite the step 1 with area initial =3119.82 km2

3119.82 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

3119.82:100\\x:8.75\\\frac{3119.82}{100}=\frac{x}{8.75}\\x=\frac{3119.82*8.75}{100} \\x=272.99\\

at the end of the year 5, the area will be

3119.82-272.99=2846.92

this will be the initial area for the year  6.

Step 6

year six

repite the step 1 with area initial =2846.92km2

2846.92 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

2846.92:100\\x:8.75\\\frac{2846.92}{100}=\frac{x}{8.75}\\x=\frac{2846.92*8.75}{100} \\x=249.10\\

at the end of the year six, the area will be

2846.92-249.10=2597.82 square kilometers

Have a great day.

8 0
3 years ago
Attachment Mathswatch!!
inna [77]

Answer:

y=3x+1

Step-by-step explanation:

y=mx+c

Gradient is 3

Rise/run=3/1=3

Y intercept=1

y=3x+1

4 0
3 years ago
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The line below are parallel. If the green line has a slope of -1/2, what is the slope of the red line?
MAXImum [283]

The line below are parallel so they have same slopes

If the green line has a slope of -1/2, the slope of the red line is also - 1/2

Answer

-1/2

4 0
3 years ago
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